1) The domain is represented in interval notation as [0, 20]. 2) The range is denoted as [100, 700]. Given that Beth saves $30 per month for 20 months and started with an account of $100, we express the total amount saved as Y = $100 + $30 × X, allowing us to accurately define both the domain and range.
Answer:
50 Educators
Step-by-step explanation:
To tackle this question, the initial step is to calculate the amount of teachers prior to the addition of new staff. For this, I devised Model 1. In this model, teachers are positioned at the top of the ratio and students at the bottom. The variable X represents the number of teachers we are determining. Utilizing this model, I computed 2,100 multiplied by 1 (2,100) and then divided by 14 to conclude there were 150 teachers. Next, I formed a similar model with the updated student-teacher ratio (Model 2). This time, I multiplied 2,100 by 2 (which is 4,200) and divided by 21 to ascertain there are 200 teachers. Having established both the initial and the increased counts of educators, subtracting the original from the new gives you the tally of new teachers, which results in an increase of 50 teachers.
The digit 7 in 75390 is in the ten thousand position, 5 is in the thousand position, 3 is in the hundreds position, 9 is in the tens position, and 1 is located in the ones position.
Given:
Two identical parallelograms total area = 9 1/3 yd²
Each parallelogram has height 1 1/3 yd
Area formula: area = base × height
Split the total area equally to find each parallelogram's area.
Convert 9 1/3: (9*3)+1 = 28/3
Divide by 2: 28/3 × 1/2 = 28/6 yd², which is 4 4/6 yd² → 4 2/3 yd²
So each parallelogram's area is 4 2/3 yd²
Set up base × 1 1/3 yd = 4 2/3 yd²
Convert and divide: 14/3 yd² ÷ 4/3 yd = base
Multiply: 14/3 × 3/4 = base
Compute: 14*3 / 3*4 = base
42 / 12 = base
Which simplifies to 3 6/12 yd = base
or 3 1/2 yd = base
a) Each parallelogram has a base of 3 1/2 yards
b) If the two parallelograms form a rectangle:
Rectangle area = length × width
Length = 3 1/2 yd × 2 = 7 yds
Width = 3 1/2 yds
Area = 7 yd × 3 1/2 yd
Area = 7 × 7/2 yd²
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²
