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Marat540
2 months ago
5

Guidelines for the jolly blue giant health insurance company say that the average hospitalization for a triple hernia operation

should not exceed 30 hours. a diligent auditor studied records of 16 randomly chosen triple hernia operations at hackmore hospital, and found a mean hospital stay of 40 hours with a standard deviation of 20 hours. "aha!" she cried, "the average stay exceeds the guideline." the p-value for a right-tailed test of her hypothesis is:
Mathematics
1 answer:
babunello [11.8K]2 months ago
6 0

To tackle this issue, we need to utilize the t statistic. This requires calculating the t score first and then consulting standard distribution tables to find the corresponding p value based on the obtained t score.

 

The formula for calculating the t score is:

t = (x – μ) / (σ / sqrt(n))

 

Where,

x = sample mean = 40

n = number of sample subjects = 16

s = standard deviation = 20

μ = Population Mean = 30

 

Plugging in the known values:

t = (40 – 30) / (20 / sqrt 16)

t = 10 / 5

t = 2

 

Utilizing the standard distribution tables and calculating the degrees of freedom, which is n – 1 = 15, we then find:

p = 0.032

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The Naturally Made Bath and Body store pays $550 a month for rent and utilities. The average cost for its products to be manufac
Leona [12618]

Answer:

220 items must be sold to achieve break-even.

Step-by-step explanation:

550 + 3.00x = 5.50x

550 = 2.50x

220 = x

6 0
1 month ago
Read 2 more answers
12. Venu and Tanuj are running along a circular track. They take 48 seconds and 56 seconds to
AnnZ [12381]

Response:

The first time they meet again at the starting point happens after 336 seconds.

Venu completes 7 laps, while Tanuj finishes 6 laps.

Detailed explanation:

Venu and Tanuj require 48 seconds and 56 seconds, respectively, to finish one lap.

To reconvene at the starting point, the time must be a multiple of both 56 and 48.

Thus, the earliest time they can meet again at the starting position is when they first clash.

This aforementioned first meeting time represents the smallest number divisible by both 56 and 48, which is 336 seconds or equivalently 5 minutes and 36 seconds.

Number of laps by Venu

=\frac{336}{48}=7

Number of laps by Tanuj

=\frac{336}{56}=6

8 0
2 months ago
If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe
AnnZ [12381]
If 49 cars are lined up and extend 528 feet, what would the average length per car be, assuming they are bumper-to-bumper? The result can be calculated as follows: we know the number of cars (49) and the total length (528 feet). Therefore, the average length is calculated as 528 feet divided by 49, which gives an average length of about 10.78 feet.
6 0
2 months ago
a speed limit of 100 kilometers per hour is approximately equal to 62 miles per hour. write an equation relating kilometers per
Svet_ta [12734]
The conversion between these units is 1 km/hr = 0.62 m/hr
8 0
2 months ago
Read 2 more answers
On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl
lawyer [12517]

Answer:

0.40

Step-by-step explanation:

The percentage of members who engage only in long-distance running is 8%

Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08

The percentage of members who participate exclusively in field events is 32%

Thus, the probability of a member competing only in field events is P(B) = 0.32

The percentage of members acting as sprinters is 12%

So, the probability that a member is a sprinter is P(C) = 0.12

We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:

P(A or B) = P(A) + P(B)

Substituting the known values results in:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40

7 0
1 month ago
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