The attached graph shows the moment when his catch surfaced at (35, 0). Given that it ascends consistently, the graph is linear. We need to establish the starting depth before he reeled it in. Using the equation d=rt, where d represents depth, r is the speed, and t is the time, we can find the distance traveled to reach the surface. Setting up the equation yields: d = 0.1(35). This indicates the catch traveled 3.5 m from a starting point of 3.5 m underwater, ascending at a rate of 0.1 m per second.
Answer: 5 Cans
Step-by-step explanation:
Let
denote the length of the pond and <span> signify its width. It's recognized that the pond's volume equals the area of its base multiplied by its depth. In this case, the base area can be computed as volume divided by depth, equating to 72000 in³ divided by 24 in, resulting in an area of 3000 in². Given that the area is expressed as x multiplied by y, we come to equation 1, 3000 = x * y. If we have x = 2y, we substitute this into equation 1, leading to 3000 = (2y) * y, simplifying to 2y² = 3000 and consequently y² = 1500, giving y = 38.7 in. Thus, x = 2y yields x = 2 * 38.7 = 77.4 in. The conclusion is that the pond's length is 77.4 in while its width is 38.7 in.
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The formula to calculate the difference between two standard deviations of populations n1 and n2 is:
sigma (difference)=√(sigma1/n1 + sigma2/n2). For this scenario:
sigma(d)= √(49/100 + 36/50)
Thus, the calculated standard deviation of the difference equals 1.1.
