You surveyed 350 students, out of which 182 were unsure.
The calculation gives: 182/350 = 0.52, indicating that 52% of the students were uncertain.
Now, apply this percentage to the national survey total:
50,000 x 0.52 = 26,000
The final result is 26,000 students who wouldn't know.
Answer:
To inspect a batch consisting of 20 semiconductor chips, a sample of 3 is selected. Out of these, 10 chips fail to meet customer specifications.
a) Total distinct samples possible = 20C3 =
=1140
b) For exactly 2 good chips and 1 bad chip
Total samples = 10C2 * 10C1 = 45 * 10 =450
c) Combinations of 2 good 1 bad, 1 good 2 bad, and 3 bad chips
Total samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
= 
Answer:
Expiration Date: 1/17/2017
Expiration Time: 4:00am
Preparation Date: 12/3/2016
Preparation Time: 4:00am
Initial Usage Date: 12/7/2016
Detailed Breakdown:
An illustrative depiction of the question has been provided in an image format for clarity.
From the information given, it is noted that her store order arrived on 12/3/2016 at 4am, confirming that both the prep date and time are 12/3/2016 and 4am respectively. The product has a printed expiration date of 1/17/2017, logically indicating that its expiration time is also 4am, in line with the prep time; adding 24 hours leads us back to the same time on the expiration date. Furthermore, we were informed that she utilized the product on 12/7/2016, which marks the initial use date. Based on this information, we can summarize as follows:
Expiration Date: 1/17/2017
Expiration Time: 4:00am
Preparation Date: 12/3/2016
Preparation Time: 4:00am
Initial Usage Date: 12/7/2016
The behavior of the spring can be described using either a sine or cosine function. The spring's maximum displacement is 6 inches, occurring at t=0, which we will define as the positive peak. Therefore, we can express the function as:
6sin(at+B). The spring's period is 4 minutes, which means the time factor in the equation must complete a cycle (2π) in 4 minutes. This gives us the equation 4min*a=2π, leading to a=π/2. Generally, a=2π/T where a is the coefficient and T is the period. For B, since sin(π/2)=1, we determine B=π/2 because at t=0, the equation becomes 6sin(B)=6. Therefore, we substitute to form f(t)=6sin(πt/2+π/2)=6cos(πt/2)
due to trigonometric relations.