Answer:
The principle behind how computer systems operate involves a primary machine-based function that remains invisible to us, serving as a control center that changes the input data into output. This central element known as the central processing unit (CPU) illustrates that the operation of computers is quite intricate.
Explanation:
This code is in Python. I'm not certain what programming language you need.
Refer to the image:
Response:
Procedure:
1. Define and set the variable one_dog_year to 7.
2.Request the user to input the dog's age.
2.1 Capture the entered dog age and store it in variable "dog_age".
3.Generate a variable "human_age" for the corresponding human age.
3.1 Compute the equivalent human age using the formula "human_age=one_dog_year*dog_age".
4.Display the calculated human age that corresponds to the dog's age.
7. Conclude the program.
// following is the algorithm executed in c++
#include <bits/stdc++.h>
using namespace std;
int main()
{
// set one dog year
int one_dog_year=7;
int dog_age;
int equi_h_age;
cout<<"Enter the dog age:";
// get the dog age
cin>>dog_age;
//determine the corresponding human age
equi_h_age=dog_age*one_dog_year;
cout<<"equivalent human age is: "<<equi_h_age<<endl;
return 0;
}
Result:
Enter the dog age:2
equivalent human age is: 14
The data for the middle node shows as –250.... Please outline the pseudocode to substitute the middle node in the linked list. Assume that the head pointer is designated as Head_ptr and the entry data for the new node is defined as Entry.
Answer:
Below is the explanation for the C code.
Explanation:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int userNum;
bool isPositive;
bool isEven;
scanf("%d", &userNum);
isPositive = (userNum > 0);
isEven = ((userNum % 2) == 0);
if(isPositive && isEven){
printf("Positive even number");
}
else if(isPositive &&!isEven){
printf("Positive number");
}
else{
printf("Not a positive number");
}
printf("\n");
return 0;
}
