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Answer:

B. Random and unforeseen occurrences take place in the real world, causing the Lotka-Volterra parameters to change with time.

Explanation:

Lotka-Volterra equations are mathematical representations that illustrate the interactions between predator and prey species, based on these assumptions:

• The ecosystem is closed, with no migration events.
• All individuals are considered reproductively similar.

• In the absence of predators, prey populations exhibit exponential growth, thriving in optimal conditions.

• If predators are absent, their population declines exponentially, limited by prey availability in an ideal environment.

• The rate of predation correlates with the frequency of encounters, which is density-dependent.

• Predators influence prey populations, leading to a decrease proportional to both predator and prey numbers.

• Conversely, prey population also affects predator numbers based on encounter ratios.

In these equations, variable D denotes predator count, while P represents prey count.

The constants remain unchanged:

• r1: prey growth rate.

• a1: predator hunting efficiency.

• r2: predator growth rate.

• a2: predator success rate in feeding and hunting.

In nature, various factors influence interactions, including density-dependent and density-independent factors. Additionally, real-world situations are affected by stochastic elements. Stochasticity represents the variations in the system caused by elements that impact population growth. This variability may correlate with prosperous and challenging years.

During a real scenario, the full adherence to the assumptions is unlikely. The previously mentioned constants can fluctuate, leading to changing interactions between predator and prey populations. Different variations lead to different experiences for both species.

Different allele frequencies are expected in the two groups.

North American:

72 birds altogether => 144 total alleles

From 72, 55 birds have short plumes, hence 17 are short-plumed.

q^2 = (2*17) / 114 = 0.236

Frequency(short plume allele) = q = 0.486

Frequency(long plume allele) = p = 1 - q = 0.514

Thus, from the North American group:

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds totaling => 504 alleles

Out of 252 birds, 75 have long plumage, 177 are short-plumed.

q^2 = (2*177) / 504 = 0.702

Frequency(short plume allele) = q = 0.838

Frequency(long plume allele) = p = 1 - q = 0.162

Thus, from this South American group:

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

For the combined population:

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population reflects the p and q from this blended result. It consists of 1000 individuals. The share of long plumed birds will be the sum of homozygous long plumed and heterozygous long plumed, calculated as: p^2 + 2pq, which you multiply by the population count of 1000 for the outcome.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (final result)