If the indicated parents produced 192 peas, the anticipated count of green and round offspring is thirty-six.
Further Explanation:
A recessive trait emerges when an organism is in a homozygous recessive condition. This indicates that individuals exhibiting a recessive trait must have both recessive alleles, as the dominant allele conceals its expression.
A monohybrid cross involves a cross between first generation organisms that vary by one trait only. The resulting ratio in the F1 generation is 1:2:1. A Punnett square is primarily employed to predict possible genetic outcomes of a monohybrid cross. Conversely, a dihybrid cross features two traits.
The total offspring in the dihybrid cross is 192. The F2 generation's plant ratios from the dihybrid cross are 9:3:3:1.
Thus, the fractions are:
Yellow round offspring at 9/16
Green round offspring at 3/16
Yellow wrinkled offspring at 3/16
Green wrinkled offspring at 1/16.
The count of green and round offspring can thus be calculated:
Green round seed = 3/16
= 3/16 × 192
= 576/16
= 36
Thus, from 192 peas, 36 will be green and round.
Learn more:
- Learn more about graffain follicle
- Learn more about human sperm and egg cells
- Learn more about female reproductive tract
Answer Details:
Grade: High School
Subject: Biology
Chapter: Mendelian Inheritance
Keywords:
Generation, plant, pea, monohybrid, dihybrid, cross, offspring, trait, present, green, round, yellow, wrinkled, dominant, recessive.
