Answer
(a) dy/dt = 68 - 3.72t
(b) 64.28 m/s
Step-by-step explanation:
Given y = 68t - 1.86t²
The average speed describes the change in distance over time, represented by dy/dt.
To find dy/dt, we differentiate y with respect to t, resulting in:
dy/dt = 68 - 2(1.86)t
= 68 - 3.72t
(a) dy/dt = 68 - 3.72t
(b) To determine the speed at t = 1, input t = 1 into dy/dt.
dy/dt at t = 1 is:
68 - 3.72(1)
= 68 - 3.72
= 64.28
The speed at t = 1 amounts to 64.28 m/s