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Gnesinka
13 days ago
11

Robby had 4 4/9 bags of pet food.All of the bags held the same amount of food when they were full.Of Robby's 4 4/9 bags of pet f

ood,2/5 were dog food.How many bags of dog food did Robby have?
Mathematics
1 answer:
Zina [3.9K]13 days ago
4 0

Respuesta: 1.8 bolsas

Explicación paso a paso:

A partir de la pregunta, considerando que Robby tiene 4 4/9 bolsas de comida para mascotas, 2/5 eran comida para perros.

2/5 de 4 4/9 = comida para perros.

Convierte 4 4/9 a fracción impropia= 40/9.

2/5 de 40/9 implica 2/5 × 40/9.

= 16/9.

= 1.78 o 1.8.

Espero que esto sea útil, por favor marca como la mejor respuesta.

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Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [3938]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
6 days ago
Sarah can bicycle a loop around the north part of Lake Washington in 2 hours and 30 minutes. If she could increase her average s
Leona [4187]

Response:

The loop's length is roughly 49.58 km.

Step-by-step details:

Given:

Duration to cycle the loop = 2 hours and 30 minutes

It is known that;

60 minutes = 1 hour

30 minutes = 0.5 hour

therefore, 2 hours and 30 minutes = 2+0.5 = 2.5\ hrs

∴ Time to cycle the loop = 2.5 hours

Let 's' denote the cycling speed.

Denote the total loop distance as 'd'

From our understanding;

Distance equals speed times time.

Representing this as an equation we have;

d =2.5s \ \ \ \ equation \ 1

Given:

If her speed increased by 1 km/hr, the time taken around the loop would decrease by 7 minutes.

As a result, we can say;

Speed =s+1

The time then will be shortened by 7 minutes.

7 minutes = 0.12 hours

Consequently, time = 2.5 - 0.12 = 2.38

Again, Distance is calculated as speed times time.

This can be expressed with equations;

d =2.38(s+1) \ \ \ \ equation \ 2

The distances are equivalent in both scenarios, thus we will determine speed by equating the equations.

2.5s = 2.38(s+1)\\\\2.5s=2.38s+2.38\\\\2.5s-2.38s =2.38\\\\0.12s= 2.38\\\\s =\frac{2.38}{0.12} \approx 19.83\ km/hr

So, Speed = 19.83 km/hr

Loop length (d) = 19.83\times 2.5 = 49.58 \ km

Therefore, the loop length is approximately 49.58 km.

7 0
5 days ago
About 400,000 people visited an art museum in December. What could be the exact number of people who visited the art museum
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The precise answer is 359,572.
8 0
9 days ago
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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
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Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

8/a = 2/3

By cross-multiplying, we find:

8 x 3 = 2a

Therefore, 24 = 2a

This leads to a = 12.

Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

12/b = 2/3

Cross-multiplying gives:

12 x 3 = 2b

So, 36 = 2b, leading to b = 18.

Denote the number of sweets on day one as x. If one-third of x was eaten and 18 remained, we can set up the equation:

18/x = 2/3

Again, cross-multiplying results in:

18 x 3 = 2x

Which simplifies to 54 = 2x, yielding x = 27.

Thus, Tim received 27 sweets at the start.

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12 days ago
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Conclusion:

Please refer to the explanation provided.

Detailed explanation:

Starting with these facts:

Total revenue = $250

Fee charged = $70 per car

Tips received = $50

Equation 1 representing the above:

(Fee per car × number of cars) + tips = total revenue

Let the number of cars be c.

Thus, we have:

$70c + $50 = $250

Part B:

Total revenue = $250

Fee charged = $75 per car

Tips received = $35

Supplies cost per car washed = $5

Equation 2:

(Fee per car × number of cars) + tips - (supplies cost × number of cars) = total revenue

$75c + $35 - $5c = $250

$70c + $35 = $250

Part C:

Equation 1 does not factor in costs associated with washing the car, while equation 2 does incorporate costs, which are deducted from the amount charged per car. Additionally, tips in equation 1 total $50 compared to a $35 fee in equation 2.

3 0
16 days ago
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