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Brums
2 months ago
6

Here is the five-number summary for a group of 100 runners in a 5-kilometer race. the variable is the time to complete the race.

five-number summary: minimum: 15 minutes q1: 27 minutes median: 31 minutes q3: 32 minutes maximum: 50 minutes are there any outliers in the runners’ finish times by the 1.5 * iqr definition?
Mathematics
1 answer:
Inessa [12.5K]2 months ago
3 0
To find the IQR (Interquartile Range) from the given information: Minimum = 15 min, Q1 = 27 min (25th percentile), Q2 = 31 min (median), Q3 = 32 min (75th percentile), Maximum = 50 min. The IQR calculation is IQR = Q3 - Q1 = 32 - 27 = 5. For identifying outliers, apply the k = 1.5 rule. The expected range is [Q1 - 1.5*IQR, Q3 + 1.5*IQR] = [27 - 1.5*5, 32 + 1.5*5] = [19.5, 39.5]. The actual range is [15, 50]. The minimum value is below 19.5, and the maximum value exceeds 39.5. Hence, outliers are present. Conclusion: Outliers exist.
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Answer:

Step-by-step explanation:

a) A diameter is a straight line that bisects a circle through its center. Line AD serves as a diameter.

The radius is half that of the diameter, which means AD/2 = AO or OD

A chord connects two points on the circumference of a circle but does not come through the center; it traverses segments of the circle instead. For instance, line FH is a chord

A tangent touches the circumference of the circle at one specific point and can contact any point along the circle's edge. Examples of tangent lines include AB and DE.

b) It's essential to know that the angles around a point or within a circle total 360°.

<EOH + <ECH = 360°

If <EOH = 131°

then <ECH = 360° - 131°

which results in <ECH = 229°

- <EFH is situated within the circle's circumference. Additionally, the angle at a circle's center is double that of the angle at the circumference. Therefore, since <EOH is at the circle’s center, <EFH = <EOH/2

Thus, <EFH = 131/2

so <EFH = 65.5°

c) Since AB = DE, it follows that <AB = <DE (equal and opposite angles). Given <AOB = 20°, then <DE = 20°

d) According to the illustration, <GFD = <GLD

If <GFD = 126°, then <GLD will likewise be 126°

e) Let HK = x+4, FK = x+14, GK = x, and CK = x+32

From the figure, we have CG = CK + KG

This means CG = x+32+x

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Also, FH = FK + HK

So, FH = x+14+x+4

thus FH = 2x+18

4 0
1 month ago
Points A, P, and B are collinear on AB, and PB:AB = 2/7. A is located on the origin (0,0), P is located at (10, -5), and B is lo
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1 month ago
What is the solution to the linear equation? 2.8y + 6 + 0.2y = 5y – 14 y = –10 y = –1 y = 1 y = 10
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Now, divide by 2:

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