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Over
2 months ago
7

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the

specified axis. x = 8y2, y ≥ 0, x = 8; about y = 2
Mathematics
1 answer:
zzz [12.3K]2 months ago
4 0

Answer:

Step-by-step explanation:

If you graph this on a Cartesian coordinate system, it resembles a logarithmic function. It begins at (0, 0) and concludes, based on the boundaries provided, at x = 8. Since we are finding the volume using the shell method, we need to establish x = y equations (which we fortunately have) as well as y intervals. The y-interval is specified in the problem as 0≤y≤2. When we rotate this solid around the line y = 2, since the axis of rotation is above the solid, we need to work backwards to reach there. This is crucial. The formula we apply for shells is

2\pi\int\limits^2_0 {p(y)h(y)} \, dy

where p(y) refers to the distance from the axis of rotation to the solid, and h(y) signifies the height of the rectangle we represent. Notably, since we utilize the shell method, this rectangle is aligned parallel to the axis of rotation, thus, it has a height of 8 units.

Here, p(y) is the distance from y = 2 to the solid, hence p(y) = 2 - y

h(y) represents the rectangle's height, therefore h(y) = 8

and inserting values into the formula gives us:

2\pi\int\limits^2_0 {(2-y)(8)} \, dy and simplifying slightly:

2\pi\int\limits^2_0 {16-8y} \, dy

Integrating yields

2\pi[16y-4y^2] from 2 to 0. Leveraging the First Fundamental Theorem of Calculus results in:

2\pi[(32-16)-(0)] which ultimately simplifies to

2\pi(16) which is, finally,

V=32 \pi

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The maximum number of identical dental care bags the dentist can create with the smallest leftover is 1.

The counts of bags are 2, 4, and 3, respectively.

Clarification:

Total tubes of toothpaste = 56

Total packets of floss = 112

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Therefore, the greatest number of identical dental care bags the dentist can assemble with minimal leftover for toothbrushes is found by calculating the H.C.F of 56, 112, 85 = 1 ( ∵ as they are coprime to each other )

Given that there is no common factor among 56, 112, and 85, except for the commonality between 56 and 112, which is 56, the remainder of toothbrushes will be 85-56=29.

Thus considering 28,[TAG_24]]

The numbers can be expressed as follows: 56 = 28×2, 112 = 28×4, and 84 = 28×3

Consequently, the dentist can create 28 bags containing all three supplies, with no leftover from toothpaste and floss, but with leftover from toothbrushes as we substitute 84 for 85 to maintain divisibility by 28 for common factor demonstration.

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1 month ago
The graphs of f(x) = 10x and its translation, g(x), are shown. On a coordinate plane, 2 exponential functions are shown. f (x) a
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Answer:

g(x)=(10)^{x-3}

Detailed explanation:

* Let’s clarify the procedure for solving this problem

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- If b > 1, it qualifies as an exponential growth function

- If 0 < b < 1, it is categorized as an exponential decay function

- Horizontal translation to the right by h units results in the new function being g(x)=a(b)^{x-h}

- Conversely, if translated to the left by h units, the function modifies to g(x)=a(b)^{x+h}

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- A vertical upward shift by k units alters the function to g(x)=a(b)^{x}+k

- A vertical downward shift by k units means the new function accounts for g(x)=a(b)^{x}-k

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∵ f(x) is an exponential function

∵ The points (0, 1), (1, 10), (2, 100) are points of f(x)

- g(x) is the transformation of f(x)

∵ The points (3, 1), (4, 10), (5, 100) belong to g(x)

∵ The point (0, 1) on f(x) transforms to (3, 1) on g(x)

∵ The point (1, 10) on f(x) transforms to (4, 10) on g(x)

∵ The point (2, 100) on f(x) translates to (5, 100) on g(x)

∵ Notably, all y-coordinates of f(x) match those of g(x)

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∴ Hence, no vertical translation occurred

∵ The x-coordinates of f(x) are increased by

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∴ This shows that f(x) is translated 3 units to the right

∵ f(x)=(10)^{x}

∴ g(x)=(10)^{x-3}

- Refer to the corresponding graph for greater clarity

# The red curve denotes f(x)

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