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nexus9112
14 days ago
7

An online news source reports that the proportion of smartphone owners who use a certain operating system is 0.216. Two simulati

ons will be conducted to create a sampling distribution of the sample proportion from a population with proportion 0.216. Simulation A will consist of 1,000 trials with a sample size of 50. Simulation B will consist of 500 trials with a sample size of 100.
Mathematics
1 answer:
Leona [4.1K]14 days ago
4 0

Answer:

The mean and center will be nearly identical, while the variability in simulation B will exceed that of simulation A.

Step-by-step explanation:

Solution

In general, the size of the sample significantly influences the distribution.

As a guideline, by quadrupling the sample size, the sampling error typically reduces by half.

Here, simulation B has a sample size that is twice that of simulation A.

Thus, the sampling error related to the mean is affected, and it stands that A does not have a greater value.

However, its sample size is considerable for this context, making them nearly equal.

Additionally, increased trials lead to decreased variability in simulation. A displays lesser variability.

As trial numbers increase, variability in simulation declines, hence A has lesser variability.

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If a study determines the difference in average salary for subpopulations of people with blue eyes and people with brown eyes is
Leona [4187]
Unlikely to have a significant difference.
8 0
7 days ago
A factory received a shipment of 38 sprockets, and the vendor who sold the items knows there are 5 sprockets in the shipment tha
tester [3938]

Answer:

a) 0.00019923%

b) 47.28%

Step-by-step explanation:

a) To determine the likelihood that all sockets in the sample are defective, we can use the following approach:

The first socket is among a group that has 5 defective out of 38, leading to a probability of 5/38.

The second socket is then taken from a group of 4 defective out of 37, following the selection of the first defective socket, resulting in a probability of 4/37.

Extending this logic, the chance of having all 5 defective sockets is computed as: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%.

b) Using similar reasoning as in part a, the first socket has a probability of 33/38 of not being defective as it's chosen from a set where 33 sockets are functionally sound. The next socket has a proportion of 32/37, and this continues onward.

The overall probability calculates to (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%.

5 0
7 days ago
Miguel spends $100 on books, five of which are hardcover and the remaining four are paperback. The prices at the bookstore are b
babunello [3666]

Answer:

$10

Step-by-step explanation:

Each hardcover book costs $12, resulting in a total of $60 for five of them out of $100. The remaining four paperbacks at $10 each amount to a total of $40.

I hope this was helpful!!!:)

6 0
11 days ago
Kate begins solving the equation StartFraction 2 Over 3 EndFraction left-parenthesis 6 x minus 3 right-parenthesis equals StartF
Leona [4187]

Answer:

(B) There is a single solution: x = 0.

Step-by-step explanation:

The equation that Kate is attempting to solve is: \dfrac{2}{3} (6x-3)=\dfrac{1}{2}(6x-4)

\dfrac{2(6x-3)}{3}=\dfrac{(6x-4)}{2}\\\dfrac{2*3(2x-1)}{3}=\dfrac{2(3x-2)}{2}\\4x-2=3x-2\\$Adding two both sides$\\4x=3x\\4x-3x=0\\x=0

Consequently, this equation results in one solution: x = 0.

4 0
6 days ago
An element with mass 570 grams decays by 26.9% per minute. How much of the element is remaining after 14 minutes, to the nearest
Svet_ta [4341]

Respuesta:

la cantidad de elemento restante después de 14 minutos = 7.091 g =~ 10 g

Explicación paso a paso:

Después de cada minuto, la cantidad que queda será

(100 - 26.9) % es decir, 73.1 %

lo que equivale a 0.731 veces la cantidad inicial.

Si el tiempo transcurrido se representa como t, la función f(t) indica la masa del elemento restante, nuestra ecuación será

f(t) = 570(0.731) ^ t

t= 14 minutos

f(14) = 570 (0.731) ^ 14

= 7.091 g =~ 10 g

8 0
2 days ago
Read 2 more answers
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