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vova2212
1 month ago
7

Suppose the dealer incentive per vehicle for honda's acura brand in 2012 is thought to be bell-shaped and symmetrical with a mea

n of $2500 anda standard deviation of $300. Based in this information,
what interval of dealer incentives would we expect approximately 99.7% of vehicles to fall within?
Mathematics
1 answer:
lawyer [12.5K]1 month ago
8 0

Answer:

Between $1600 and $3400.

Step-by-step explanation:

According to the Empirical Rule, for a normally distributed random variable:

68% of values are found within 1 standard deviation of the mean.

95% of values reside within 2 standard deviations of the mean.

99.7% of values lie within 3 standard deviations of the mean.

Given data indicates:

Mean = 2500

Standard deviation = 300

What range of dealer incentives would accommodate approximately 99.7% of vehicles?

By applying the Empirical Rule, 99.7% are found within 3 standard deviations from the mean. Therefore,[[@TAG_34]]From 2500 - 3*300 = 1600 to 2500 + 3*300 = 3400.

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As a part-time contractor, you want to test a new cement mixture for a project. You need 2 34 wheelbarrows of sand to make 8 whe
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Answer: He will require 10.07 cubic feet of sand for the wheelbarrows.

Step-by-step explanation:

Given that

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(\dfrac{11}{32})^3=\dfrac{x}{248}\\\\\dfrac{1331\times 248}{32^3}=x\\\\10.07=x

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Keitaro walks at a pace of 3 miles per hour and runs at a pace of 6 miles per hour. Each month, he wants to complete at least 36
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Answer:

Option 1 is valid, which entails 2 hours of walking and 12 hours of running.

Step-by-step explanation:

The equations provided are:

3w + 6r ≥ 36

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We'll assess which options comply with these equations.

1) 2 hours walking; 12 hours running

w = 2 and r = 12

3w + 6r ≥ 36

3(2) + 6(12) ≥ 36

6+72 ≥ 36

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3w + 6r ≤ 90

3(2) + 6(12) ≤ 90

6+72 ≤ 90

78 ≤ 90

Both equations are satisfied. Option 1 is valid.

2) 4 hours walking; 3 hours running

w = 4 and r = 3

3w + 6r ≥ 36

3(4) + 6(3) ≥ 36

12+18 ≥ 36

30 ≥ 36 (this does not hold since 30 < 36)

3w + 6r ≤ 90

3(4) + 6(3) ≤ 90

12+18 ≤ 90

30 ≤ 90

Thus, Option 2 is invalid.

3) 9 hours running; 12 hours walking

w = 9 and r = 12

3w + 6r ≥ 36

3(9) + 6(12) ≥ 36

27+72 ≥ 36

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3w + 6r ≤ 90

3(9) + 6(12) ≤ 90

27+72 ≤ 90

99 ≤ 90 (this does not hold since 99 > 90)

Option 3 is invalid.

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3w + 6r ≥ 36

3(12) + 6(10) ≥ 36

36+60 ≥ 36

96 ≥ 36

3w + 6r ≤ 90

3(12) + 6(10) ≤ 90

36 + 60 ≤ 90

96 ≤ 90 (this does not hold since 96 > 90)

So, Option 4 is invalid.

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