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2 answers:
Answer:
Bottom-left corner.
Step-by-step explanation:
To solve this, assess the function for x=0, which denotes the intersection with the Y-axis. When h(x) = x^3 + 2x^2 - 11x - 12 is evaluated at x=0
y=-12
Thus, the coordinate is (0,-12)
Among the graphs, two adhere to this description. Now we evaluate the intersection with the X-axis, noting that at y=0, x=-4
To verify, apply h(x) = x^3 + 2x^2 - 11x - 12 for x=-4 and check if it equals 0:
The function yields 0, confirming that this graph represents h(x) = x^3 + 2x^2 - 11x - 12
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