Answer:
a. A relative-frequency distribution relates to a variable just as a _____probability_____ distribution relates to a random variable. b. A relative-frequency histogram pertains to a variable similarly to how a _____probability_____ histogram pertains to a random variable.
Step-by-step explanation:
Probability, a mathematical concept, involves numerical assessments of how likely a certain event may occur, indicating the validity of its occurrence. The range for the probability of any event is typically between 0 and 1,
with 0 signifying impossibility and 1 indicating certainty of occurrence.
a) P(identified as explosive) equals P(actual explosive & identified as explosive) + P(not explosive & identified as explosive) = (10/(4*10^6))*0.95+(1-10/(4*10^6))*0.005 = 0.005002363. Thus, the probability that it actually contains explosives given that it's identified as containing explosives is (10/(4*10^6))*0.95/0.005002363 = 0.000475. b) Let the probability of correctly identifying a bag without explosives be a. Therefore, a = 0.99999763, approximately 99.999763%. c) No, even if this becomes 1, the true proportion of explosives will always be below half of the total detected.
Answer:
The four odd numbers in sequence are 89, 90, 91, and 93.
Step-by-step explanation:
Designate the four consecutive numbers as x, x+2, x+4, and x+6.
Based on the information given in the question
x + (x + 2) + (x + 4) + (x + 6) = 368
4x + 12 = 368
4x = 356
x = 89
Consequently, the numbers are 89, 90, 91, and 93.
Hope this is helpful:)
Answer:
A), B), and C) are clarified below.
Step-by-step explanation:
The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.
Simplifying gives us
P[k] = nCk / 2^n
A. Probability of all bits being 1s
16c16/2^16 = 1/65536
B. Probability of all bits being 0s
16c0/2^16 = 1/65536
C. The probability of having exactly 8 bits as 1s and the other 8 as 0s
16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%
