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nadezda
5 days ago
13

At a large university, data were collected on the number of sisters and brothers that each student had. Let the random variable

XX represent the number of sisters and the random variable YY represent the number of brothers. The distribution of XX has mean 1.00 and standard deviation 0.94. The distribution of YY has mean 1.07 and standard deviation 1.04. What is the mean of the distribution of X YX Y
Mathematics
1 answer:
babunello [8.4K]5 days ago
8 0
2.07. The mean for X is calculated as 1.00, and for Y as 1.07, leading to the total of X + Y = 1 + 1.07 = 2.07.
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Question

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Step-by-step explanation:

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\frac{4mn}{m^{-2}n^6}

Required:

Simplify

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Thus, the aforementioned expression can be restated similarly

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From the indices laws

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So,

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Therefore, \frac{4mn}{m^{-2}n^6} can be regarded as \frac{4m^3}{n^5}

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