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ANEK
2 months ago
11

A group of friends is attempting free throws on a basketball court. The table shows the number of attempts and the number of bas

kets each player made. Name Attempts Baskets Made Finn 16 12 Michael 18 16 Jeff 8 6 Tanner 6 4 Kevin 12 9 Tristan 10 10 The players’ attempts and baskets made are plotted on the graph. Determine which players had the same ratio of attempts to baskets, and select their corresponding points on the graph.

Mathematics
2 answers:
tester [12.3K]2 months ago
6 0

Response:

The Second, Fourth, and Fifth dots on the graph

Finn Jeff Kevin


lawyer [12.5K]2 months ago
3 0

Response:

Finn, Jeff, and Kevin

Detailed explanation:

The ratios of attempts to baskets are

Finn = 16/12 = 4/3

Michael = 18/16 = 9/8

Jeff = 8/6 = 4/3

Tanner = 6/4 = 3/2

Kevin = 12/9 = 4/3

Tristan = 10/10 = 1

Consequently, Finn, Jeff, and Kevin share identical ratios of attempts to baskets.

The accompanying graph illustrates attempts versus baskets.

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zzz [12365]
What was the amount of ziti consumed?

5 0
2 months ago
Which expression is equivalent to (3m^-2n)^-3/6mn^-2? Assume m=0, n=0.
Inessa [12570]
This is the solution:

(3m^-2 n)^-3 / 6mn^-2
For the first step: apply the power distribution3^-3 m^-2*-3 n^-3 / 6mn^-2
In the second step: utilize the product and quotient rulesm^6 n^2/ 3^3 *6*m*n^3
Lastly, simplify the expressionm^5/162n
The conclusive answer is m^5/162n

Hope this aids you.:)
8 0
1 month ago
Read 2 more answers
An urn contains 3 red and 7 black balls. Players and withdraw balls from the urn consecutively until a red ball is selected. Fin
Leona [12618]

Correct question:

An urn holds 3 red and 7 black balls. Players A and B take turns withdrawing balls until a red one is chosen. Calculate the probability that A picks the red ball. (A goes first, followed by B, with no replacement of drawn balls).

Answer:

The likelihood that A picks the red ball is 58.33 %

Step-by-step explanation:

A will select the red ball if it is drawn 1st, 3rd, 5th, or 7th.

1st draw: 9C2

3rd draw: 7C2

5th draw: 5C2

7th draw: 3C2

Calculating for all possible scenarios gives us:

9C2 = (9!) / (7!2!) = 36

7C2 = (7!) / (5!2!) = 21

5C2 = (5!) / (3!2!) = 10

3C2 = (3!) / (2!) = 3

Adding these possibilities results in 36 + 21 + 10 + 3 = 70.

The total outcomes for selecting a red ball = 10C3

10C3 = (10!) / (7!3!)

= 120.

The probability that A selects the red ball is determined by dividing the sum of possible events by the overall outcomes.

P( A selects the red ball) = 70 / 120

= 0.5833

= 58.33 %

7 0
2 months ago
Assume that a study of 500 randomly selected airplane routes showed that 482 arrived on time. Select the correct interpretation
babunello [11817]

Answer: C. Significant at 0.036

Step-by-step explanation:

Given:

Total samples selected Ns= 500

Airplanes that arrived on time Na = 482.

Airplanes that arrived late Nl = 500 - 482 = 18

Calculating the probability of an airplane arriving late:

P(L) = Nl/Ns

P(L) = 18/500

P(L) = 0.036

An event is deemed significant if its probability is equal to or less than 0.05.

As P(L) < 0.05

P(L) = Significant at 0.036

4 0
2 months ago
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