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otez555
1 month ago
7

Your order is supposed to be delivered between 5PM-6PM, and it’s now 5:45PM. You’re stuck in a long line waiting to check out. I

n this situation, you will be late delivering the order. Provide an example of the text message you would send to the member.
Business
2 answers:
marusya05 [3.7K]1 month ago
8 0

If I were caught in traffic and had to deliver a parcel between 5 PM and 6 PM, I would notify the customer of the delay.

Additional Explanation:

Sample message explaining the delay:

Hi, Dear "customer name", your parcel with shipment number "012365232" will be delayed and is expected to be delivered the next working day. Thank you.

Alternative example:

Dear "customer name", your parcel is delayed due to heavy traffic. We apologize for the inconvenience and expect delivery within the next hour. Thank you for your understanding.

Thank you very much. Feel free to adapt this message for your own company communications.

Free_Kalibri [3.7K]1 month ago
6 0

Explanation:

Imagine being stuck in a long queue at checkout when you’re meant to deliver a parcel between 5 PM and 6 PM. In this case, you would inform the recipient by text about the delay, explaining the situation and providing a new time frame. An example message might be:

Hi Sir/Madam,

This is abc from xyz company. Your parcel was scheduled to arrive between 5 PM and 6 PM, but due to unforeseen circumstances, there will be a slight delay. We expect your parcel to be delivered within the next hour.

We appreciate your patience and apologize for the inconvenience.

Best Regards.

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A certain insurance company charges Mike's wife $250 for a one-year $100,000 life insurance policy. Because Mike is a 21 year-ol
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Answer:

X      |    100000      -250

P(X)  |     0.0015     0.9985

E(X)= \sum_{i=1}^n X_i P(X_i)

And substituting in gives us:

E(X) =100000*0.0015 -250*0.9985= -99.625

Explanation:

This scenario defines the random variable X as Mike's wife's profit on the specific one-year life insurance policy.

Given that the company charges $250 for a one-year $100,000 life insurance policy, and knowing the probability of Mike living for a year is 0.9985, we find the chance he will not live for the year as 1 - 0.9985 = 0.0015.

Thus, the probability distribution is represented as follows:

X      |    100000      -250

P(X)  |     0.0015     0.9985

Now we can compute the expected value for that year:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing provides:

E(X) =100000*0.0015 -250*0.9985= -99.625

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