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lisabon 2012
2 months ago
15

Tim has 39 pairs of headphones and 13 music players. Tim wants to sell all of the headphones and music players in identical pack

ages.
What is the greatest number of packages Tim can make?
Mathematics
2 answers:
Leona [12.6K]2 months ago
8 0

Answer:

he is able to create 4 packages hope this helps

Leona [12.6K]2 months ago
8 0
He is able to create 4 packages
You might be interested in
If y varies directly as x, and y is 400 when x is r and y is r when x is 4, what is the numeric constant of variation in this
Leona [12618]

Answer:

10

Step-by-step explanation:

If there’s a direct correlation between variables x and y, it can be expressed as

y = kx,

where y is the dependent variable

x is the independent variable

k signifies the constant of variation

_____________________________

For the first scenario

y = 400

x = r

using y = kx, we can derive the relation:

400 = kr

To find k here:

k = 400/r

For the second scenario

y = r

x = 4

again using y = kx, the relationship is given by:

r = 4k

Solving for k:

k = r/4

Since both conditions provide the same equation, k will have the same value in both cases.

Thus, we conclude:

400/r = r/4

=> 400*4 = r*r

=> 1600 = r^2

\sqrt{r^{2} } = \sqrt{1600} \\r = 40

Hence, r is calculated to be 40.

Thus, k = r/4 = 40/4 = 10.

The constant of variation is confirmed to be 10, which is the correct answer.

Verification:

k = 400/r = 400/40 = 10

7 0
2 months ago
Read 2 more answers
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
zzz [12365]

Answer:

A.) 1508; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

The general equation for an exponential model is:

A = A0e^rt

A0 represents the initial population

A indicates the final population

r is the growth rate; t denotes time

1)

Considering the years 1750 and 1800

Time interval, t = 1800 - 1750 = 50 years

Starting population = 790

End population = 980

To find the growth rate:

980 = 790e^50r

980/790 = e^50r

Applying the natural logarithm to both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this growth rate, let's forecast the population for 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788; approximately 1508 million people

In 1950:

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467; around 1870 million people

2.)

Exponential model from 1800 to 1850

Initial population in 1800 = 980

Final population in 1850 = 1260

t = 1850 - 1800 = 50

Utilizing the exponential equation, we find the growth rate:

1260 = 980e^50r

1260/980 = e^50r

Taking the natural logarithm of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Utilizing this model, the anticipated population in 1950:

In 1950:

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571; approximately 2083 million people

3.)

For 1900: 1650,

For 1950: 2560

t = 1900 - 1950 = 50

Utilizing the exponential formula, we derive the growth rate:

2560 = 1650e^50r

2560/1650 = e^50r

Logarithm both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using this model, the projected population for 2000:

In 2000:

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787; approximately 3972 million people

3 0
2 months ago
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