Sam needs to score 97 on his upcoming test to keep his average at 85. If you total 63, 84, 96, and 97, the sum is 340. Dividing 340 by four test scores yields an exact average of 85.
Assuming a maximum rental duration of 8 days, if we apply this to the equation, Happy Harry's Rentals costs $500, while Smilin' Sam's charges $600. Therefore, for the 7th and 8th days, Happy Harry's Rentals is a better option, while Smilin' Sam's is preferable for the first six days.
The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.
For m₁: m₁*g - T = m₁*a
For m₂: T - m₂*g = m₂*a
Assuming a massless cord and pulley without friction, the accelerations are the same.
From the second equation: a = (T - m₂*g) / m₂
Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g
This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>
Conclusion:
Please refer to the explanation provided.
Detailed explanation:
Starting with these facts:
Total revenue = $250
Fee charged = $70 per car
Tips received = $50
Equation 1 representing the above:
(Fee per car × number of cars) + tips = total revenue
Let the number of cars be c.
Thus, we have:
$70c + $50 = $250
Part B:
Total revenue = $250
Fee charged = $75 per car
Tips received = $35
Supplies cost per car washed = $5
Equation 2:
(Fee per car × number of cars) + tips - (supplies cost × number of cars) = total revenue
$75c + $35 - $5c = $250
$70c + $35 = $250
Part C:
Equation 1 does not factor in costs associated with washing the car, while equation 2 does incorporate costs, which are deducted from the amount charged per car. Additionally, tips in equation 1 total $50 compared to a $35 fee in equation 2.