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nlexa
2 months ago
15

You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $1; if

the faces are both heads, you win $6; if the coins do not match (one shows a head, the other a tail), you lose $3 (win (−$3)). Calculate the mean and variance of Y, your winnings on a single play of the game. Note that E(Y) > 0.
Mathematics
1 answer:
Zina [12.3K]2 months ago
6 0

Answer: The mean and variance of Y are $0.25 and $6.19 respectively.

Step-by-step explanation:

The scenario is as follows: You and a friend participate in a game involving tossing a fair coin.

The sample space for tossing two coins is {TT, HT, TH, HH}

Let Y represent the earnings from one round of the game.

If both faces are heads, you win $1; therefore, P(Y=1)=P(TT)=\dfrac{1}{4}=0.25

You win $6 if both faces are heads, so P(Y=6)=P(HH)=\dfrac{1}{4}=0.25

If the faces do not match, you lose $3 which means P(Y=1)=P(TH, HT)=\dfrac{2}{4}=0.50

To find the expected value to win: E(Y)=\sum_{i=1}^{i=3} y_ip(y_1)

=1\times0.25+6\times0.25+(-3)\times0.50=0.25

Thus, the mean of Y: E(Y)= $0.25

E(Y^2)=\sum_{i=1}^{i=3} y_i^2p(y_i)\\\\=1^2\times0.25+6^1\times0.25+(-3)^2\times0.5\\\\=0.25+1.5+4.5=6.25

Variance = E[Y^2]-E(Y)^2

=6.25-(0.25)^2=6.25-0.0625=6.1875\approx6.19

Therefore, variance of Y = $ 6.19

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<span>P(black socks): 24/42 or 12/21
P(black socks without replacement): 23/41. Consequently, the chance of randomly selecting 2 black socks, without replacement, from the basket is 12/21×23/41=276/861, equivalent to 32%. Hope this helps!</span>
6 0
2 months ago
Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
Leona [12618]

Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

8/a = 2/3

By cross-multiplying, we find:

8 x 3 = 2a

Therefore, 24 = 2a

This leads to a = 12.

Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

12/b = 2/3

Cross-multiplying gives:

12 x 3 = 2b

So, 36 = 2b, leading to b = 18.

Denote the number of sweets on day one as x. If one-third of x was eaten and 18 remained, we can set up the equation:

18/x = 2/3

Again, cross-multiplying results in:

18 x 3 = 2x

Which simplifies to 54 = 2x, yielding x = 27.

Thus, Tim received 27 sweets at the start.

3 0
3 months ago
Two ferries travel across a lake 50 miles wide. One ferry goes 5 miles per hour slower than the other. If the slower ferry leave
Svet_ta [12734]

Answer:

Step-by-step explanation:

Let x represent the speed of the first ferry.

Consequently, the second ferry's speed is x-5, as it travels 5 miles per hour slower.

The time taken by the first ferry is calculated as distance divided by speed = \frac{50}{x}

The time taken by the second ferry equals \frac{50}{x-5}.

Since the second ferry departs one hour earlier, the times differ by 1 hour.

\frac{50}{x-5}-\frac{50}{x}=1\\50x-50(x-5)=x(x-5)\\250 = x^2-5x\\x^2-5x-250 =0\\(x-10)(x+5) =0\\x=18.5, -13.5

The speed cannot be negative.

Thus, the speed of the first ferry is determined to be 18.5 mph,

and for the second, slower ferry, it equals 13.5 mph.

5 0
3 months ago
Write the number with the same value as 28 tens
zzz [12365]

It is understood that

One tens corresponds to the number -----------> 10

thus

28 tens translates to

28*10=280

hence

the result is

280


3 0
3 months ago
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Answer:

B

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