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Iteru
2 months ago
6

Which one of the following statements is NOT true of a free-falling object? An object in a state of free fall ____.

Mathematics
1 answer:
AnnZ [12.3K]2 months ago
5 0
Hello! C and D aren't correct answers, as they fall downward due to gravity. The object accelerates downward at -10 m/s, resulting in an increasing speed as it descends, going beyond 10 m/s, which indicates that speed isn't steady. Hence, the correct answer is A.
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Juanita and Samuel are planning a pizza party. They order a rectangle sheet pizza that measures 21 inches by 36 inches.?They tel
Svet_ta [12734]
To begin, calculate the entire area of the pizza. The area of a rectangle is determined by multiplying its length and width.

Area = 21 x 36 = 756 square inches

Next, we must divide the total area with the largest possible square configuration without any leftovers. Thus, we equate the pizza's area to that of a square:

A = s² = 756
s = 6 √21

Therefore, the maximum achievable square piece has a side measuring 6 inches. We then divide the pizza's total area by the area of each square unit to ascertain the quantity of pieces;

756/6² = 21

Hence, 21 pieces of 6-inch square pizza can be cut.
7 0
1 month ago
Find the missing term in the following sequence ? 1, 4, 11, 26, 57, 120, ______
babunello [11817]

Answer:

247

Step-by-step explanation:

1, 4, 11, 26, 57, 120. The emerging pattern of the series is as follows:

4–1 = 3; 3–1 = 2 = 2^1

11–4 = 7; 7 - 3 = 4 = 2^2

26 - 11 = 15; 15 - 7 = 8 = 2^3

57 - 26 = 31; 31 - 15 = 16 = 2^4

120 - 57 = 63; 63 - 31 = 32 = 2^5

Thus, the next number should be 64+63 = 127+120 = 247.

Verification: 247–120 = 127; 127–63 = 64 = 2^6, which checks out.

So, the following number is indeed 247. 2^n+(n-1)

5 0
2 months ago
Read 2 more answers
The chance of winning a certain game at a carnival is 2 in 5. If Andy plays the game 12 times, what is the probability that he l
PIT_PIT [12445]

Answer:

There is a 1.5267% chance that he loses AT MOST 3 times.

Step-by-step explanation:

Each game Andy plays has only two outcomes: a win or a loss. The probability of winning doesn’t depend on previous games, leading us to use the binomial probability distribution for this situation.

Binomial probability distribution

This distribution calculates the probability of achieving exactly x successes in n trials with only two possible outcomes for X.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

Where C_{n,x} signifies the various combinations of x objects from a set of n elements, calculated using:

C_{n,x} = \frac{n!}{x!(n-x)!}

And p represents the likelihood of X occurring.

The winning probability for a certain carnival game is 2 out of 5.

This implies a losing chance of (5-2) in 5, equaling 3 out of 5.

Thus, p = \frac{3}{5} = 0.6

Considering 12 games:

Consequently, n = 12.

What probability is there that he loses AT MOST 3 times?

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3).

Where:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.6)^{0}.(0.4)^{12} = 0.000017

P(X = 1) = C_{12,1}.(0.6)^{1}.(0.4)^{11} = 0.000302

P(X = 2) = C_{12,2}.(0.6)^{2}.(0.4)^{10} = 0.002491

P(X = 3) = C_{12,3}.(0.6)^{3}.(0.4)^{9} = 0.012457

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.000017 + 0.000302 + 0.002491 + 0.012457 = 0.015267

The likelihood of losing AT MOST 3 times is 1.5267%.

6 0
2 months ago
An earthquake registers a 5.6 on the Richter scale. If the reference intensity of this quake was 7.3 × 109, what was the intensi
babunello [11817]
By solving the equation Log(x/7300000000) = 5.6, we can express it as follows: x/7300000000 = 10^5.8 which equals 398107.17. Therefore, after performing the necessary calculations, we find that x equals approximately 2.9061823 x 10^15.
8 0
1 month ago
Read 2 more answers
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