Answer:
Detailed steps:
y – 4 = –1 (x – 2)
y – 7 = –1 (x + 1)
y = –x + 6
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Important details about isosceles triangle ABC:
- The median CD, which is drawn to the base AB, also acts as an altitude to that base in the isosceles triangle (CD⊥AB). This indicates that triangles ACD and BCD are congruent right triangles, each with hypotenuses AC and BC.
- In isosceles triangle ABC, the sides AB and BC are equal, meaning AC=BC.
- The base angles at AB are equal, m∠A=m∠B=30°.
1. Consider the right triangle ACD. The angle adjacent to side AD is 30°, which dictates that the hypotenuse AC is double the length of the opposite side CD relating to angle A.
AC=2CD.
2. Now, for right triangle BCD, the angle next to side BD is also 30°, so hypotenuse BC is twice the opposite leg CD linked to angle B.
BC=2CD.
3. To calculate the perimeters of triangles ACD, BCD, and ABC:



4. If the total of the perimeters of triangles ACD and BCD is 20 cm greater than the perimeter of triangle ABC, then

5. Given that AC=BC=2CD, the lengths of legs AC and BC of the isosceles triangles are 20 cm.
Answer: 20 cm.
The area would amount to 25
and we could create 3 squares. This would leave 75
5 inches remaining.
Response:

Detailed breakdown:
Considering a rectangle measuring 3cm by 4cm with a circle of 1 cm diameter within it:
The area of the shaded section equals Area of Rectangle minus Area of Circle
The area of a rectangle is calculated as Length multiplied by Width

The area of the circle is

Area of shaded region = 12 - 3.142
