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MariettaO
1 month ago
5

Of the 1,000 students in a local college, 420 own brand X mobile phones and 580 own brand Y mobile phones. Of these students, 80

own both brands of mobile phones. Find the probability that a student chosen at random has a brand X mobile phone given that he has a brand Y mobile phone.
A. 2/14

B. 5/21

C. 3/28

D. 4/29
Mathematics
1 answer:
Inessa [12.5K]1 month ago
8 0
P(X \ Y) = P(X ∩ Y)/P(Y)
P(X ∩ Y) = 80/1000 = 0.08
P(Y) = 580/1000 = 0.58

P(X \ Y) = 0.08/0.58 = 8/58 = 4/29
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Joaquin is four more than half Marjorie’s age. Marjorie is also 32 less than three times Joaquin’s age.
babunello [11817]

Answer:

Her age is 40 years

Step-by-step explanation:

Let Jerry's age be represented as j

Let Marjorie's age be denoted as m

The first part of the question states:

j = 4 + m/2

For the second equation:

m = 3j - 32

Multiply the first equation by 2 to get:

2j = 8 + m

Leading to m = 2j - 8

Set both equations for m equal to each other:

2j - 8 = 3j - 32

By simplifying, we get:

3j - 2j = 32 - 8

Therefore, j = 24

Now substituting back:

m = 2j - 8

m = 2(24) - 8

Thus, m = 48 - 8

Final result: m = 40

5 0
1 month ago
An arena receives $1,700 per event for 12 concerts. If the costs for this sponsorship total $14,000, what is the profit margin f
Zina [12379]

Answer:

The profit margin associated with the concert sponsorship is 31.3725 %

Step-by-step explanation:

The arena earns $1700 for a single event

Consequently, for 12 events, the arena gains 12 \times 1700

The total for 12 events equals 20400

The expenses for this sponsorship amount to $14,000

Thus, profit = 20400-14000

This calculates to profit =6400

To find the profit margin =\frac{6400}{20400} \times 100

Profit margin is defined as 31.3725\%

Thus, the profit margin for the concert sponsorship is 31.3725 %

6 0
19 days ago
Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa
zzz [12365]

Answer:

We conclude that less than or equal to 50% of the student body supports him significantly.

Step-by-step explanation:

Mike, while campaigning for the student government presidency, is keen to determine if more than 50% of the student body supports him.

A random sample of 100 students was surveyed, with 55 expressing support for Mike.

Let p = the proportion of students backing Mike.

Thus, Null Hypothesis, H_0: p \leq 50% {indicating that the proportion of supporters among the student body is significantly less than or equal to 50%}

Alternate Hypothesis, H_A: p > 50% {indicating that the proportion of supporters among the student body is significantly more than 50%}

The test statistics to be utilized here One-sample z proportion statistics;

T.S. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = the sampled proportion in favor of Mike = \frac{55}{100} = 0.55

n = number of sampled students = 100

Therefore, test statistics = \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

= 1.01

The z test statistic is 1.01.

At a significance level of 0.05, the z table provides a critical value of 1.645 for a right-tailed test.

Given that our test statistic falls below the critical value of z (1.01 < 1.645), we lack sufficient evidence to reject the null hypothesis as it remains outside the rejection region, leading to failure to reject our null hypothesis.

As a result, we conclude that less than or equal to 50% of the student body is in favor of him or the proportion supporting Mike is not significantly greater than 50%.

4 0
1 month ago
Triangles ΔABC ≅ ΔBAD so that C and D lie in the opposite semi-planes of segment AB. Prove that segment CD bisects segment AD.
Zina [12379]

Answer:

Review the explanation

Step-by-step explanation:

The triangles ΔABC and ΔBAD are congruent, establishing:

  • AB ≅ BA;
  • AC ≅ BD;
  • BC ≅ AD;
  • ∠ABC ≅ ∠BAD;
  • ∠BCA ≅ ∠ADB;
  • ∠CAB ≅ ∠DBA.

Now, consider triangles AEC and BED. In these triangles, we have:

  • AC ≅ BD;
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  • ∠AEC ≅ ∠BED (being vertical angles).

Therefore, ΔAEC ≅ ΔBED, which leads to the conclusion that:

AE ≅ EB.

This indicates that line segment CD bisects segment AD.

6 0
1 month ago
A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC onto ∆A′B′C′ is a followed by
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The sequence ABC is oriented clockwise in both diagrams, indicating an even number of reflections or a rotation.

A 90° clockwise rotation about the point (-3, -3) would accomplish the necessary transformation, but that is not a listed option. An equivalent action is...
   • reflect across the line x = -3
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11 days ago
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