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Lorico
11 days ago
14

Let event A= the place is a city. Let event B=the place is in North America. which outcomes are in A or B

Mathematics
1 answer:
AnnZ [10.8K]11 days ago
5 0
All possible outcomes fall under either A or B, which includes any results that are classified as being a city, located within North America, or both. Thus, the resulting possibilities within A or B are: Tokyo, Houston, New York, Tijuana, Canada.
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m∠3 is (3x + 4)° and m∠5 is (2x + 11)°. Angles 3 and 5 are . The equation can be used to solve for x. m∠5 = °
zzz [10799]

I recently completed this question!

Here are the answers:

1) same side interior angles

2) (3x+4)+(2x+11) = 180

3) 77


7 0
1 month ago
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Please enter the missing number: 2, 9, 20, 37, 64, 107, ?
Leona [11060]
The missing number is 174.
4 0
22 days ago
Eight identical slips of paper, each containing one number from one to eight, inclusive, are mixed up inside a bag. Subset A of
PIT_PIT [10955]

Answer: The correct choice is (C) A = {1, 2, 3, 4, 5, 7, 8}.

Step-by-step explanation: We have eight identical slips of paper, each numbered from one to eight, which have been mixed inside a bag.

The sample space, S is as follows:

S = {1, 2, 3, 4, 5, 6, 7, 8}.

Subset A consists of the complement of the event where the number 6 is drawn.

Let 'B' denote the event of drawing the number 6.

Thus, B = {6}.

Since 'A' represents the complement of 'B', it will include all elements in the sample space 'S' that are not part of set 'B'.

Therefore,

A = B' = {1, 2, 3, 4, 5, 7, 8}

So, A = {1, 2, 3, 4, 5, 7, 8}.

Consequently, (C) is the correct choice.

7 0
1 month ago
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"A sample of 20 randomly chosen water melons was taken from a large population, and their weights were measured. The mean weight
AnnZ [10855]

Answer: (97.98, 112.020)

Step-by-step explanation: We will create a 95% confidence interval for the average weight of melons.

Given the information, we determine that the critical value for the interval needs to be retrieved from a t distribution table due to the sample size being below 30 (specifically, 20), and we are provided with the sample standard deviation (s = 15 lb).

The parameters provided are:

Sample mean = x = 105 lb

Sample standard deviation = s = 15 lb

Sample size = n = 20

To establish the 95% confidence interval, we indicate that the level of significance is 5%.

The formula for the confidence interval is:

u = x + tα/2 × s/√n... for the upper limit

u = x - tα/2 × s/√n... for the lower limit.

tα/2 represents the critical value for the test (which will be determined using the t distribution table).

To derive tα/2, we look for the value based on the degrees of freedom (sample size - 1) against the significance level for a two-tailed test (α/2 = 0.025%) in a t distribution table.

For the upper limit, we calculate:

u = 105 + 2.093×15/√20

u = 105 + 2.093× (3.3541)

u = 105 + 7.020

u = 112.020.

<pfor the="" lower="" limit="" we="" find:="">

u = 105 - 2.093×15/√20

u = 105 - 2.093× (3.3541)

u = 105 - 7.020

u = 97.98

Confidence interval (97.98, 112.020)

</pfor>
6 0
1 month ago
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
Svet_ta [11257]

We are given the triangle

△ABC, with m∠A=60° and m∠C=45°, and AB=8.

To start, we will calculate all angles and sides.

Finding angle B:

The total of all angles in a triangle equals 180.

m∠A + m∠B + m∠C = 180.

Substituting the known values,

60° + m∠B + 45° = 180.

This gives us m∠B = 75°.

Calculating BC:

Using the law of sines,

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

We can substitute in the values.

\frac{8}{sin(45)}=\frac{BC}{sin(60)}

BC=\frac{8}{sin(45)} \times sin(60)

BC=9.798

Finding AC:

\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

Now we'll input the values.

\frac{8}{sin(45)}=\frac{AC}{sin(75)}

AC=\frac{8}{sin(45)} \times sin(75)

AC=10.928

Calculating Perimeter:

p=AB+BC+AC

We substitute values here as well.

p=10.928+8+9.798

p=28.726

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Using the area formula,

A=\frac{1}{2}AB \times AC \times sin(A)

we can then insert values.

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A=37.85570...............Answer

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1 month ago
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