answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hram777
2 days ago
7

Machines at a factory produce circular washers with a specified diameter. The quality control manager at the factory periodicall

y tests a random sample of washers to be sure that greater than 90 percent of the washers are produced with the specified diameter. The null hypothesis of the test is that the proportion of all washers produced with the specified diameter is equal to 90 percent. The alternative hypothesis is that the proportion of all washers produced with the specified diameter is greater than 90 percent.
Which of the following describes a Type I error that could result from the test?

A) The test does not provide convincing evidence that the proportion is greater than 90%, but the actual proportion is greater than 90%.

B) The test does not provide convincing evidence that the proportion is greater than 90%, but the actual proportion is equal to 90%.

C) The test provides convincing evidence that the proportion is greater than 90%, but the actual proportion is equal to 90%.

D) The test provides convincing evidence that the proportion is greater than 90%, but the actual proportion is greater than 90%.

E) A Type I error is not possible for this hypothesis test.
Mathematics
1 answer:
zzz [9K]2 days ago
0 0

Answer:

A Type I error could occur if the test shows that the proportion is above 90%, while in reality, the actual proportion is 90%.

Step-by-step explanation:

Machines in a factory produce circular washers that meet a specific diameter.

The quality control manager routinely assesses samples of washers to ensure that more than 90% conform to the specified diameter.

Let p represent the proportion of washers that meet the specified diameter

Thus, Null hypothesis: p = 90% H_0

Alternative Hypothesis: p > 90%H_A

Here, the null hypothesis posits that the proportion is exactly 90%. In contrast, the alternative hypothesis suggests that the proportion exceeds 90%.

Now, a Type I error indicates the probability of rejecting the null hypothesis while it is actually true or, in simple terms, the likelihood of incorrectly rejecting a valid hypothesis.

Thus, based on our question, a Type I error would declare that the test convincingly indicates the proportion is over 90%, while in truth, it remains 90%.

You might be interested in
Use the normal approximation to the binomial distribution to answer this question. Fifteen percent of all students at a large un
AnnZ [9099]

Answer: 0.1289

Step-by-step explanation:

Given: The proportion of students absent on Mondays at a large university.: p=0.15

Sample size: n=12

Mean: \mu=np=12\times0.15=1.8

Standard deviation = \sigma=\sqrt{np(1-p)}

\Rightarrow\ \sigma=\sqrt{12(0.15)(1-0.15)}=1.23693168769\approx1.2369

Let x represent a binomial variable.

Referencing the standard normal distribution table,

P(x=4)=P(x\leq4)-P(x\leq3) (1)

Z score for normal distribution:-

z=\dfrac{x-\mu}{\sigma}

For x=4

z=\dfrac{4-1.8}{1.2369}\approx1.78

For x=3

z=\dfrac{3-1.8}{1.2369}\approx0.97

Thus, from (1)

P(x=4)=P(z\leq1.78)-P(z\leq0.97)\\\\=0.962462-0.8339768\approx0.1289

Consequently, the likelihood of four students being absent = 0.1289

3 0
23 days ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
babunello [8412]

Response:

the expected value of this raffle if you purchase 1 ticket = -0.65

Breakdown of the calculation:

Details:

5,000 tickets are sold at​ $1 each for a charitable raffle

Winners will be chosen at random with cash prizes as follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Therefore, the value and its respective probability can be calculated as follows:

Value                              Probability

$500 - $1 = $499              1/5000

$300 - $1 = $299              3/5000

$50 - $1 = $49                    5/5000

$5 - $1 = $4                     20/5000

-$1                           1 - 29/5000 = 4971/5000

The expected value of the raffle when buying 1 ticket is computed as follows:

E(x) = \sum x * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000} + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016 + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

So, the expected value of this raffle when one ticket is purchased = -0.65

7 0
7 days ago
Chiang is filling a 50ft container with water at a rate of 0.5 ft/ min. interpret the key features for this situation
Leona [9271]

Answer:

The main aspects are

50ft³ = volume

0.5ft³/min = filling rate

Time= 100 minutes

Step-by-step breakdown:

Chiang is in the process of filling a 50ft container with water at a speed of 0.5 ft/min.

50ft³ = volume

0.5ft³/min = flow rate

It’s important to note that we still need to determine how long it will take to fill the 50 ft³ container.

Time = volume / rate

Time = 50 ft³ / 0.5 ft³/min

Time = 50 / 0.5 min

Time = 100 min

The main aspects are

50ft³ = volume

0.5ft³/min = filling rate

Time= 100 minutes

7 0
1 month ago
Find a solution to the linear equation 13x + y = 26 by filling in the boxes with a valid value of x and y.
Inessa [9000]

Answer:

MOM

Step-by-step explanation:

6 0
5 days ago
Find the annual rate of growth (interest rate) on an account that was worth $200 in 1975 and $415.79 in 1990
tester [8842]
To find the percent change over time, use the following formula: PR = Percent Rate, VPresent = Present or Future Value, VPast = Past or Present Value. The annual percentage growth rate is calculated by dividing the percent growth by N, which is the number of years. The calculation (415.79 - 200) / 200 * 100 results in 107.89. The annual percentage growth rate is then 107.89 divided by 15, which equals 7.193.
8 0
7 days ago
Read 2 more answers
Other questions:
  • The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous ran- dom variable with a cumulat
    7·1 answer
  • Find the truth set of each predicate. (If your answer is an interval, enter it using interval notation; otherwise enter it as a
    13·1 answer
  • Three books (x, y, and z) rest on a table. x is on table, while y is stacked upon x, and z is stacked upon y. the weights of the
    11·1 answer
  • If (a^3+27)=(a+3)(a^2+ma+9) then m equals
    7·1 answer
  • Nina's monthly budget is $2,250. Every month she makes the following payments: $175 for insurance, $129 for utilities, $283 for
    10·2 answers
  • Assume that TUV=WXY which of the following congruence statements are correct
    7·2 answers
  • Frances has no money in her checking account. she writes 3 checks for $35 each. the bank imposes $15 penalty because she has ove
    9·2 answers
  • A weather station in a major city in the Northwest kept data about the weather conditions over the past year. The probabilities
    13·2 answers
  • Create a pattern for the rule a x 3 + 2
    14·1 answer
  • Which points are on the perpendicular bisector of the given segment? Check all that apply. Please explain how you got your answe
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!