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2 days ago

Setting StartFraction 7 over 3 EndFraction equal to which ratio would result in a valid proportion?

2 answers:

6 0

Option C is correct. Step-by-step explanation: We need to identify which options are equivalent to 7/3. By evaluating each option: Option A: 9/49 is incorrect as it cannot be further simplified to yield multiples adequate to match. Option B: 18/42 reduces to 3/7, which does not equal 7/3, hence, incorrect. Option C: 42/18 divides down to 7/3, marking it as the correct choice. Option D: 49/9 also cannot be simplified to produce valid multiples.

Leona [9.2K]2 days ago

3 0

C, the solution is 18/4

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A CD has a 5% chance of being a smash hit and profiting $5.2 million, a 50% chance of being a modest success and profiting $0.9

Zina [9179]

P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'

5 0

1 month ago

What is the value of x in the equation 4 x plus 8 y equals 40, when y equals 0.8? 4.6 8.4 10 12What is the value of a in the equ

AnnZ [9104]

Answer:

1. 8.4 2. 15

Step-by-step explanation:

1. 4x + 8y = 40

when y = 0.8

4x + 8 × 0.8 = 40

4x = 40 - 8 × 0.8

4x = 40 - 6.4 = 33.6

....x = 33.6 / 4 = 8.4

2. 3a + b = 54

when b = 9

3a + 9 = 54

3a = 54 - 9

3a = 45

.....a = 45 / 3 = 15

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8 0

24 days ago

Read 2 more answers

Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 emp

Zina [9179]

Answer:

a) The likelihood that none of the sampled employees are from the Hawaii plant is 1.74%.

b) The chance that exactly 1 employee from the sample is found working in the Hawaii plant is 8.70%.

c) There is an 89.56% chance that 2 or more employees in the sample are from the Hawaii plant.

d) The probability that 9 employees from the sample are working at the Texas plant is 8.70%.

Step-by-step explanation:

Each employee has two potential employment locations: either Texas or Hawaii. Thus, the binomial probability distribution can be utilized to solve this scenario.

Binomial probability distribution

This distribution defines the probability of achieving exactly x successes in n trials where there are only two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

Here, $C_{n,x}$ denotes the number of ways to choose x objects from a set of n, represented by the subsequent formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of success occurring.

In this context, we know:

The sample comprises 10 employees, therefore $n = 10$ .

a. Calculate the probability that none of the sampled employees are from the Hawaii plant (to 4 decimals)?

Given that 20 out of 60 employees are based in Hawaii:

$p = \frac{20}{60} = 0.333$

We aim to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.333)^{0}.(0.667)^{10} = 0.0174$

Thus, the likelihood that none in the sample are from Hawaii stands at 1.74%.

b. Calculate the probability that 1 employee from the sample is from the Hawaii plant?

This is represented as P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.333)^{1}.(0.667)^{9} = 0.0870$

Therefore, there is an 8.70% possibility that 1 employee in the sample comes from Hawaii.

c. Calculate the probability that 2 or more employees in the sample are from the Hawaii plant?

We can observe two scenarios: either fewer than 2 employees are from Hawaii or 2 and beyond. The combined probabilities equal decimal 1. So:

$P(X < 2) + P(X \geq 2) = 1$

We seek to find $P(X \geq 2)$ .

$P(X \geq 2) = 1 - P(X < 2)$

From problems a and b, we possess values for both probabilities.

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0174 + 0.0870 = 0.1044$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1044 = 0.8956$

Accordingly, the chance that 2 or more employees in this sample operate at the Hawaii plant is 89.56%.

d. Calculate the likelihood that 9 employees in the sample are working at the Texas plant?

This corresponds to the probability found in part b for 1 employee working in Hawaii.

Consequently, there is an 8.70% chance that 9 employees belong to the Texas plant.

6 0

22 days ago

A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat

Inessa [9006]

To derive the function that characterizes the bee population:

1) Initially, there are 9,000 bees in the first year.

2) In the second year, a reduction of 5% occurs => 9,000 - 0.05 * 9,000 = 9,000 * (1 - 0.05) = 9,000 * 0.95

3) Each subsequent year sees a 5% decline => 9,000 * (0.95)^(number of years)

4) Let x represent years and f(x) signify the bee count, then: f(x) = 9,000 (0.95)^x.

Evaluation of the claims:

<span>1) The function f(x) = 9,000(1.05)x applies to the scenario.

FALSE: WE ESTABLISHED IT AS f(x) = 9,000 (0.95)^x

2) The function f(x) = 9,000(0.95)x applies to the scenario.

TRUE: THIS IS THE RESULT OF OUR PRIOR ANALYSIS.

3) After 2 years, the farmer projects approximately 8,120 bees will be left.

Calculating:

f(2) = 9,000 * (0.95)^2 = 9,000 * 0.9025 = 8,122

Thus, this statement is TRUE

4) After 4 years, the farmer can predict there will be roughly 1,800 bees left.

f(4) = 9,000 * (0.95)^4 = 9,000 * 0.81450625 = 7,330

This statement is therefore FALSE

5) The domain values contextual to this situation are restricted to whole numbers.

FALSE: DOMAIN VALUES INCLUDE ALL NON-NEGATIVE REAL NUMBERS. FOR INSTANCE, THE FUNCTION IS VALID AT X = 5.5

6) The range values pertinent to this situation are restricted to whole numbers.

TRUE: FRACTIONS OF BEES CANNOT EXIST.
</span>

3 0

19 days ago

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The weights, in pounds, of Mike's five pet dogs are listed below. What is the mean absolute

Inessa [9006]

Answer:

The answer is 12

Step-by-step explanation:

7 0

1 month ago

Read 2 more answers