Let the number of two-hour lessons be x and the number of one-hour lessons be y; this gives us the equations
2x + y = 25
50x + 30y = 690
To find x and y, we can solve the quadratic equation provided;
from the first equation:
y = 25 - 2x.......i
By substituting equation i into the second equation, we arrive at:
50x + 30(25 - 2x) = 690
50x + 750 - 60x = 690
-10x = -60
So,
x = 6
Thus, we find that the total number of two-hour lessons is 6 hours.
We aim to verify the assertion that generally, 10% of students repeat a course, leading us to this hypothesis setup:
Null hypothesis:
Alternative hypothesis.
The most fitting choice for this scenario is:
d) H0:p=0.1 vs. H1:p ≠ 0.1.
For this case, the provided information includes: the number of students repeating the course, the selected sample size, and the estimated proportion of repeaters. We are testing the claim that generally, 10% of students retake classes, which will be validated through established hypotheses.
Answer:
78/4
Step-by-step explanation:
this seems correct
x = 3
-2 | 2.2(3) - 3.3 | = -6.6
-2 | 6.6 - 3.3 | = -6.6
-2 | 3.3 | = -6.6
-2 * 3.3 = -6.6
-6.6 = -6.6
