B. 5 Step-by-step explanation: The greatest common factor of 85 and 15 is 5, leading to a ratio of red to white tulips of 17:3. Red tulip ratio becomes 85/5 = 17, while white tulip ratio turns out to be 15/5 = 3.
Answer: On average, a pet's weight during this vet visit is approximately 2.4 pounds away from 12.9 pounds.
If the MAD for another day's weights was 1.5, then that day’s weights would be less variable compared to the weights of pets seen today.
Step-by-step explanation:
Given: The data in the table outlines the weights of animals visiting a vet one day, in pounds.
Mean = 12.9
Median= 12.0
Mode = 12.0
Mean Absolute Deviation = 2.4
It’s understood that the mean absolute deviation (MAD) of a dataset indicates the average distance between each data point and the mean. It reflects the variation present in the dataset.
Therefore, the average weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.
Moreover, if another day had a MAD of 1.5, and since 1.5 < 2.4,[TAG_42]]
it implies that the weights on that day would be less variable compared to those of pets encountered on this day.
Greetings,
f(1)=160
f(2)=160*(-2)
f(3)=160*(-2)²
f(4)=160*(-2)^3=-1280
The function can be expressed as f(n)=160*(-2)^(n-1)
Answer:
Step-by-step explanation:
First, we apply the Pythagorean theorem to determine the distance from Manuel’s home to the resort.
S1 = √50²+20²
S1 = √2500+400
S1 = √2900
S1 = 53.85m
Next, we find the distance from Manuel's home to his friend’s residence.
S2 = √15²+10²
S2 = √225+100
S2 = √325
S2 = 18.03m
The distance between the two boys and the resort will be represented as ∆S = S2 - S1.
∆S = 53.84 - 18.03
∆S = 35.81m
