The required work to pump water is 3,325,140 Joules. Step-by-step explanation: Work done by the pump is calculated by multiplying the force exerted on the pump by the distance the water is moved. Force equates to mass multiplied by gravitational acceleration. Consequently, Force = (water density × tank volume) × gravitational acceleration, leading to F = ρVg. Therefore, Work done = (ρVg) * d. Given the values of ρ = 1000 kg/m³, g = 9.8 m/s², d = 3 m, we compute the work done: Work = 1000 * 113.10 * 9.8 * 3 = 3,325,140 Joules.
Answer:
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Step-by-step explanation:
There can be various responses to this query. Usually, the next number following 16 has digits that add up to 8.
Explanation:
First number 31 – The digits add up to 3 + 1 = 4
Second number 1031 – The sum of the digits is 1 + 0 + 3 + 1 = 5
Third number 402 – The digits sum to 4 + 0 + 2 = 6
Fourth number 16 – Adding the digits gives 1 + 6 = 7
Thus, the missing number could either be the single digit 8 or any of these two-digit options: 17, 26, 35, 44, 53, 62, 71, or 80. It may also include larger numbers consisting of the digits from the mentioned two-digit figures combined with 0, like 260 or 7001.
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The simplified expression is 10m + 20.5, where m stands for the total number of months.
Initially, we can express her expenses as follows:
8.5 + 62.5m and 12 + 3.75m.
Adding these two expressions together yields a combined equation of:
10m + 20.5.
