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Artist 52
2 months ago
7

In the triangles, XY = MP and YZ = PN. Triangles Y X Z and P M N are shown. The length of side X Z is 23 inches. The length of s

ide M N is 19 inches. Sides X Y and M P are congruent. Sides Y Z and P N are congruent. If mAngleP = 85°, which is a possible measure for AngleY? mAngleY = 80° mAngleY = 85° mAngleY = 100° mAngleY = 180°

Mathematics
2 answers:
AnnZ [12.3K]2 months ago
5 0
I believe the correct answer must be m<Y= 100°, which corresponds to option C.
lawyer [12.5K]2 months ago
5 0
In Triangles YXZ and PMNSince the third side of the triangle formed by two congruent sides will always be congruent, the triangles are congruent by SSS congruence theorem.Therefore:If angle P = 85°Given that P and Y occupy the same positions in the two triangles respectively, angle Y must also be 85 degrees.
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Marlo uses 252 lb of gravel to cover a garden plot of 36 ft2. How many pounds of gravel does it take to cover one square foot? H
babunello [11817]

The amount of gravel and the area it covers are examples of ratios.

A weight of 7 lb can cover 1 square foot, while 315 lb can cover an area of 45 square feet.

The relevant parameters are:

252\ lb= 36ft^2

To find the number of pounds needed for 1 square foot , perform the following calculation:

x = 1ft^2

Thus, we have:

x = 1ft^2

252\ lb= 36ft^2

Cross multiply

x \times 36 = 252 \times 1

And divide both sides by 36

x = 7lb

The area that 315 lb of gravel can cover is calculated as follows:

So, we have:

315lb = y

315lb = y

Cross multiply

252\ lb= 36ft^2

y \times 252 = 36 \times 315

And divide both sides by 252

y \times 252 = 11340

Thus, 7 lb will cover

1 square footy = 45, and 315 lb will encompass an area of

45 square feet.

Read more about ratios at:

6 0
1 month ago
a golfer needs to hit a ball a distance of 500 feet, but there is a 60-foot tall tree that is 100 feet in front of the point whe
Svet_ta [12734]
We can formulate the trajectory of the parabola using the vertex form equation: y = a (x – h)^2 + k. The coordinates for the vertex are at h and k, representing the peak height, thus h = 250 and k = 120. Consequently, the equation becomes y = a (x – 250)^2 + 120. At the starting point where x = 0 and y = 0, we find a: 0 = a (0 – 250)^2 + 120, which simplifies to 0 = a (62,500) + 120, leading to a = -0.00192. The complete equation is y = -0.00192 (x – 250)^2 + 120. To determine y when x = 400, we substitute: y = -0.00192 (400 - 250)^2 + 120, yielding y = 76.8 ft. Hence, the ball clears the tree by 76.8 ft – 60 ft = 16.8 ft.
8 0
2 months ago
Find the values of x1 and x2 where the following two constraints intersect.
Inessa [12570]

Answer: x1 = 251/26, x2 = -111/26

Step-by-step explanation:

Greetings!

As illustrated in the diagram, the point you seek is where the two lines intersect.

This intersection point is found by solving the system of linear equations (both equations must be satisfied by the point):

9x_1 +7x_2=57\\4x_1 + 6x_2 = 13

You can approach solving it using the substitution method:

\text{solve for x1 in the first equation:}\\x_1 = \frac{1}{9}(57 - 7x_2)

Then substitute x1 into equation 2 to resolve x2:

\frac{4}{9}(57-7x_2) + 6x_2 = 13\\\text{doing the algebra you get:}\\x_2 = \frac{-111}{26}

After which, utilize the x2 value to establish x1:

x_1 = \frac{1}{9}(57 - 7x_2)= \frac{1}{9}(57 + 7*\frac{111}{26}) = 251/26\\

4 0
2 months ago
Suppose we are given 4 sets A, B, C, D such that A ⊆ B and C ⊆ D such that A and C have no elements in common. Prove or give a c
babunello [11817]

Here’s a counterexample: consider

B = \{1, 2, 3, 4, 5\},\quad D = \{A, B, C, D, 5\}

Select the subsets in the following manner:

A = \{1, 5\},\quad C = \{A, B, C\}

It's accurate that A\subseteq B and C\subseteq D and that A\cap C=\emptyset, but A\cap D = \{5\}

8 0
2 months ago
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