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alekssr
4 days ago
15

Lucy collects data from a random sample of seventh-graders. Out of 40 respondents, 7 attend afterschool programs. Of the 200 sev

enth-graders attending Lucy’s school, how many would be expected to attend afterschool programs?
Mathematics
1 answer:
Svet_ta [9.4K]4 days ago
8 0
From a total of 40 individuals who responded, 7 are involved in afterschool activities. \frac{7}{40}=0.175, leading to a percentage of 17.5% of the students being part of afterschool programs.
0.175*200=35.
Thus, from a group of 200 seventh-graders, one would anticipate that 35 would participate in afterschool programs.
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Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
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Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Since RS is parallel to DC, we conclude that;

∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that  ΔBCD ~ ΔBSR, we obtain;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).

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1 month ago
A set of notations (SSS, SAS, ASA and RHS) is used to describe/prove
Svet_ta [9486]

Detailed breakdown:

locate the triangles

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Julia can finish a 20-mile bike ride in 1.2 hours. Katie can finish the same bike ride in 1.6 hours. How much faster does Julia
Svet_ta [9486]

Given that,speed = \frac{distance}{time}

Julia completes a 20-mile bike ride in 1.2 hours.

The distance Julia covers is 20 miles and her time taken is 1.2 hours.

Therefore, Julia's speed = \frac{20}{1.2} = 16.67 mph


Katie finishes the same 20-mile ride in 1.6 hours.

Katie’s distance is 20 miles and her time is 1.6 hours.

Hence, Katie's speed = \frac{20}{1.6} = 12.5 mph


To determine how much faster Julia rides compared to Katie, subtract Katie’s speed from Julia’s speed.

Thus, 16.67 mph minus 12.5 mph equals 4.17 mph, approximately 4.2 mph.

Consequently, Julia cycles 4.2 mph faster than Katie.

5 0
1 month ago
Read 2 more answers
give an example on an addition problem in which you would and would not group the addends differently to add
AnnZ [9071]
Addends refer to the numbers being summed in an equation. 

Their arrangement only matters if parentheses are utilized to modify the usual Order of Operations. 

For example:
2 - (8 + 3)  in this case, 8 and 3 must be grouped first before tackling the subtraction.

Any addition scenario without parentheses can similarly function where the grouping is irrelevant.
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7 days ago
the graph shows your budget and the total cost of x gallons of gasoline and a car wash you want to determine the possible amount
lawyer [9226]

Answer:

Part a) Your budget is $40.

Part b) The price for one gallon of gasoline is $3.55, while a car wash costs $8.

Part c) x \leq 9.01\ gal

Part d) Refer to the explanation below.

Step-by-step explanation:

Please see the complete question in the attached image.

Part a) The budget is expressed by the equation

y = 40

therefore,

Your budget amounts to $40.

Part b) In terms of costs, how much is a gallon of gasoline and what is the car wash price?

Let

y ------> denote the total cost for a gallon of gasoline along with a car wash

x -----> define the volume of gasoline in gallons

We can express the relationship as

y = 3.55x + 8

For calculations, when x = 0, we have:

y = 3.55(0) + 8 = 8

The y-intercept signifies the cost of the car wash, being $8.

Now, to identify the price of one gallon of gasoline:

We know the slope of the linear function is

m = $3.55 per gallon

This confirms that a gallon of gasoline costs $3.55.

Part c) Formulate an inequality representing the potential quantity of gasoline you can purchase:

We have:

3.55x+8 \leq 40

Now, solve for x:

3.55x \leq 40-8

3.55x \leq 32

x \leq 9.01\ gal

Part d) Utilize the graph to determine the solution of the inequality from part c)

We can set up the system:

y = 40

y = 3.55x + 8

The solution lies at the intersection of both graphs. By observing the graph, the intersection appears to be around (9, 40).

This indicates that the maximum volume of gasoline purchasable within your budget is approximately 9 gallons.

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