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GalinKa
2 days ago
12

Which sequence of transformations carries abcd onto efgh

Mathematics
1 answer:
lawyer [9.2K]2 days ago
6 0

Answer:

D

Step-by-step explanation:

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The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
PIT_PIT [9117]

Answer:

The tangent plane equation for the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

We have

The ellipsoid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation for the tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  (Given)

The hyperboloid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The tangent plane equation at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The tangent plane equation for the hyperboloid is

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The tangent plane equation

2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2

Hence, the required tangent plane equation for the hyperboloid is

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

7 0
1 month ago
sari has 3 times as many pencil erasers Sam. Together, they have 28 erasers.  How many erasers does Sari have
PIT_PIT [9117]
Start by letting x represent the number of Sam's pencils. Then Sari has 3x (since she has three times as many)

Together they total 28 pencils:
x + 3x = 28
4x = 28  /:4 (divide both sides by 4)
x = 7
So Sam has 7 pencils.
Sari, having three times as many, has 7 * 3 = 21.[[TAG_8]]
4 0
9 days ago
Read 2 more answers
Value of expression 6 3/4(-11.5)
Inessa [9000]

Answer:

6 * 3/4 = 4.5 = 9/2 = 412

Step-by-step

6 * 3/4 = 6/1  3*4 = 18/4 = 9/2

2 · 2 = 9/2

Both the numerators and denominators are to be multiplied. Retain the resulting fraction with the lowest possible denominator; GCD(18, 4) = 2. In this intermediate calculation, cancelling by the common factor of 2 results in 9

2

.

In summary - six times three quarters equals nine halves.

0 0
29 days ago
Jaxon and Isaac live different directions from the city center. Jaxon lives 10 blocks east and 5 blocks north. Isaac lives 8 blo
Leona [9271]

Answer:

Step-by-step explanation:

According to the attached figure, Jaxon is positioned 10 blocks east and 5 blocks north.

Thus, Jaxon's x-coordinates are 10 units, while the y-coordinates are 5 units.

Therefore, the coordinates are given by (10,5)

Similarly, Isaac's coordinates are determined based on his distances towards the west and south.

Hence, the x-coordinates equal 8 units and the y-coordinates equal 15 units.

Thus, Isaac’s coordinates are depicted as (-8,-15).

4 0
19 days ago
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Millie has a box of 1 hundred cubes. She also has a bag of 70 cubes. How many trains of 10 cubes can she make?
Zina [9171]
Millie possesses a total of 170 cubes

170/10=17 trains
7 0
14 days ago
Read 2 more answers
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