Each of the six payments amounts to $41.50
Step-by-step breakdown:
Given,
Total cost of the bike including taxes = $349
Initial payment = $100
Remaining balance = Total cost of bike - Initial payment
Remaining balance = 349 - 100
Remaining balance = $249
She opts to pay in six equal installments, so we divide the total remaining by 6.
Monthly payment = 
Monthly payment = 
Each of the six payments amounts to $41.50
Keywords: division, subtraction
Learn more about subtraction at:
The result is 10/117. We have three distinct letters and four unique non-zero digits. For letters, we have 26 options from A to Z. For digits, there are 9 choices from 1 to 9. As all selections must be distinct, we find the total number of codes as 26 × 25 × 24 × 9 × 8 × 7 × 6. For the specified code, we focus on the combinations with 5 vowels and 4 even digits, leading to a calculation of 5 × 25 × 24 × 8 × 7 × 6 × 4. Probability can thus be expressed as the ratio of these outcomes, yielding: 5 × 25 × 24 × 8 × 7 × 6 × 4 divided by 26 × 25 × 24 × 9 × 8 × 7 × 6.
(a) The multiplicative inverse of 1234 (mod 4321) is x so that 1234*x ≡ 1 (mod 4321). We can apply Euclid's algorithm:
4321 = 1234 * 3 + 619
1234 = 619 * 1 + 615
619 = 615 * 1 + 4
615 = 4 * 153 + 3
4 = 3 * 1 + 1
Now we will express 1 as a linear combination of 4321 and 1234:
1 = 4 - 3
1 = 4 - (615 - 4 * 153) = 4 * 154 - 615
1 = 619 * 154 - 155 * (1234 - 619) = 619 * 309 - 155 * 1234
1 = (4321 - 1234 * 3) * 309 - 155 * 1234 = 4321 * 309 - 1082 * 1234
This reduces to
1 ≡ -1082 * 1234 (mod 4321)
Thus, the inverse is
-1082 ≡ 3239 (mod 4321)
(b) Since both 24140 and 40902 are even, their GCD cannot equal 1, indicating no inverse exists.
Area of a rectangle = length x width
For this postcard:
length = 4 in
width = (3+b) in
area = 24 in^2
Substitute into the area formula:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in
Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch
The domain refers to all potential input values, specifically represented by the x-axis on a graph. Conversely, the range includes all possible output values, depicted along the y-axis.
The graph clearly extends horizontally from (-∞,∞) on the x-axis, indicating that its domain is (-∞,∞).
Similarly, it can be seen that the graph stretches vertically from (-∞,∞) on the y-axis, denoting that the range is also (-∞,∞).
This indicates the function includes an infinite array of values. Therefore, there are no limitations on either the domain or the range for this function.
