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AysviL
3 months ago
5

The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) us

ing a point and the slope. Which point did Harold use? When Harold wrote his equation, the point he used was (7, 3). When Harold wrote his equation, the point he used was (0, 7). When Harold wrote his equation, the point he used was (7, 0). When Harold wrote his equation, the point he used was (3, 7).
Mathematics
2 answers:
Zina [12.3K]3 months ago
8 0

We need to identify the point Harold utilized for this equation:

y = 3 (x-7)

Recall that the point-slope form of a line is expressed as:

(y-y_ {1}) = m (x-x_ {1})

Comparing Harold's equation to the standard form reveals the line's slope is m = 3..

Furthermore, it is clear that x_ {1} = 7 and y_ {1} = 0..

Therefore, Harold's equation was based on the point (7,0).

Answer:

The point (7,0) was used by Harold when writing his equation.

PIT_PIT [12.4K]3 months ago
8 0

Answer:

c

Step-by-step explanation:

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