Write multiple if statements. If car_year is 1969 or earlier, print "Few safety features." If 1970 or later, print "Probably has

Question

10 days ago

8

Write multiple if statements. If car_year is 1969 or earlier, print "Few safety features." If 1970 or later, print "Probably has

seat belts." If 1990 or later, print "Probably has antilock brakes." If 2000 or later, print "Probably has airbags." End each phrase with a period and a newline.
Sample output for input: 1995
Probably has seat belts.
Probably has antilock brakes.

My code:

car_year = int(input())

if car_year <= 1969:
print('Few safety features.')
elif car_year ==1970:
print('Probably has seat belts.')
elif car_year >= 1990:
print('Probably has seat belts.\nProbably has antilock brakes.')
else:
car_year >= 2000
print('Probably has airbags.')

My output that keeps failing:
Testing with input: 2001
Output differs. See highlights below.
Special character legend
Your output
Probably has seat belts.
Probably has antilock brakes.
Expected output
Probably has seat belts.
Probably has antilock brakes.
Probably has airbags.

Computers and Technology

1 answer:

Amiraneli [921] · Answer 1 · 2026-03-26T15:05:00+03:00

Your issue arises from using elif and if constructs. When one of your conditions is true, the others are bypassed. Instead, you should apply multiple if statements in place of elif and else. For example:

car_year = int(input())

if car_year <= 1969:

print('Few Safety features.')

if car_year >= 1970:

print('Probably has seat belts.')

if car_year >= 1990:

print('Probably has antilock brakes.')

if car_year >= 2000:

print('Probably has airbags.')

I have implemented my code using Python 3.8. I hope this proves beneficial.