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natali 33
8 days ago
6

Sean is white hat hacker, who is demonstrating a network level session hijack attacks and as part of it, he has injected malicio

us data into the intercepted communications in the TCP session when the victim had disabled the source-routing. Which of the following network level session hijacking attack is Sean showing? a) RST Hijacking b) TCP/IP Hijacking c) Blind Hijacking d) UDP Hijacking vceguide.
Computers and Technology
1 answer:
amid [800]8 days ago
3 0

Answer:

The type of session hijacking attack that Sean is illustrating is Blind Hijacking, option C.

Explanation:

This is because he is inserting harmful data or commands into the compromised communications within the TCP session, regardless of the source-routing being turned off. He is capable of sending the data or commands, but does not have the ability to view the responses.

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Assume that the following variables have been properly declared and initialized.
ivann1987 [930]

Answer:

boolean rsvp;

int selection;

String option1;

String option2;

(a) if(rsvp){

System.out.println("Attending");

} else {

System.out.println("Not attending");

}

(b) if (selection == 1){

System.out.println("Beef");

} else if (selection == 2){

System.out.println("Chicken");

} else if (selection == 3) {

System.out.println("Pasta");

} else {

System.out.println("Fish");

}

(c) switch(selection){

case 1:

if(rsvp){

option1 = "Thanks for attending. You will be served beef.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 2:

if(rsvp){

option1 = "Thanks for attending. You will be served chicken.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 3:

if(rsvp){

option1 = "Thanks for attending. You will be served pasta.";

} else{

option1 = "Sorry you can't make it";

}

break;

default:

if(rsvp){

option1 = "Thanks for attending. You will be served fish.";

} else{

option1 = "Sorry you can't make it";

}

break;

}

(d) if (option1.equals(option2)){

System.out.println("True");

} else {

System.out.println("False");

}

Explanation:

This code is written in Java.

a) It uses an if statement to print "attending" if rsvp evaluates to true and "not attending" if rsvp is false.

b) An if-else structure determines which food choice is printed depending on user input. If selection equals 1, beef is printed; if it is 2, chicken appears; if it is 3, pasta is displayed; any other value results in fish being printed.

c) The switch statement checks the value of selection and uses an inner if statement to assign "Thanks for attending. You will be served beef." to option1 if rsvp is true. This assignment varies with the selection's value. When rsvp is false, option1 gets the message "Sorry you can't make it."

d) An if statement evaluates whether option1 and option2 are equivalent and outputs true if they match; otherwise, it indicates false.

8 0
1 month ago
A pedometer treats walking 2,000 steps as walking 1 mile. Write a program whose input is the number of steps, and whose output i
ivann1987 [930]

Response:

steps = int(input("Specify the number of steps: "))

miles = steps / 2000

print('{:.2f}'.format(miles))

Explanation:

Prompt the user to input the number of steps and convert the input to an integer.

Compute the corresponding miles by dividing the number of steps by 2000.

Output the miles formatted to two decimal places.

5 0
1 month ago
You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
ivann1987 [930]

Response: explained in the explanation section

Explanation:

Given that:

Assume D(k) =║ true if [1::: k] is a valid sequence of words, or false otherwise

  • In determining D(n)

the sub problem s[1::: k] is a valid sequence of words IFF s[1::: 1] is valid and s[ 1 + 1::: k] is a valid word.

Thus, we derive that D(k) is defined by the following recurrence relation:

D(k) = ║ false max(d[l] ∧ DICT(s[1 + 1::: k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1::: k]             ∦ array of boolean variables.

for a ← 1 to m

do;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1::: a])

d (a) ← True

(b). Algorithm Output

      if D[k] == True

stack = temp stack            ∦stack assists in displaying the strings in order

c = k

while C > 0

stack push (s [w(c)]::: C] // w(p) denotes the index in s[1::: k] of the valid word // at position c

P = W (p) - 1

output stack

= 0 =

cheers, I hope this aids you!!!

8 0
16 days ago
If a packet gets “sucked down a black hole” (figuratively speaking) and is not received by its sender, and no message is sent ba
Harlamova29_29 [932]

If a packet gets figuratively “sucked into a black hole” and is not received by the original sender, with no message returned to clarify the situation, there is an issue. This lack of communication indicates there is a problem with the _____.

A.) ICMP

B.) TCP/IP

C.) HTTP

D.) ISO

A.) ICMP

I hope this information is useful and wish you the best.

~May

0 0
1 month ago
Compute the approximate acceleration of gravity for an object above the earth's surface, assigning accel gravity with the result
maria [879]

Response:

Written in Python

G = 6.673 *pow(10,-11)

M = 5.98 *pow(10,24)

d = float(input("Enter distance: "))

g = (G * M)/(pow(d,2))

print("Calculated gravity acceleration: "+str(g))

Explanation:

The following line sets the gravitational constant

G = 6.673 *pow(10,-11)

This line establishes the mass of the Earth

M = 5.98 *pow(10,24)

This prompts the user to input the object's distance

d = float(input("Enter distance: "))

This calculates the gravity exerted on the object

g = (G * M)/(pow(d,2))

This line outputs the gravity acceleration without rounding

print("Calculated gravity acceleration: "+str(g))

8 0
1 month ago
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