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valentinak56
1 month ago
9

Tristan records the number of customers who visit the store each hour on a Saturday. His data representing the first seven hours

are 15, 23, 12, 28, 20, 18, and 23. How many customers visited the store during the eighth hour if the median number of customers per hour did not change?
Show all your work and explain how you arrived at your answer.
Mathematics
2 answers:
Leona [12.6K]1 month ago
7 0

The weekly customer visits to the store on a Saturday are recorded as 15, 23, 12, 28, 20, 18, and 23. If we organize these numbers in ascending order, we get: 12, 15, 18, 20, 23, 23, 28. The median is defined as the "middle" value within this ordered list of numbers.

In this scenario, the median stands at the middle value, which is identified as 20. We seek the number of customers who visited the store in the eighth hour to maintain a constant median of 20 per hour. Introducing an eighth number will position the median as the average of the fourth and fifth numbers. To preserve the median at 20, we should choose 20 as the eighth number, ensuring that the two middle figures are both 20, which will yield an average of 20 and thus uphold the median as 20.

The resulting set of numbers becomes 12, 15, 18, 20, 20, 23, 23, 28. Median = (20+20)÷2=20.



Svet_ta [12.7K]1 month ago
3 0
Initially, we must determine the median from the provided dataset. To achieve this, we need to sort the values:
12, 15, 18, 20, 23, 23, 28
Thus, the median appears to be 20

To ensure the median remains unchanged, the eighth hour would need to have 20 visitors, allowing the revised dataset to be:
12, 15, 18, 20, 20, 23, 23, 28

I hope this clarifies things!
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3 months ago
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The manufacturer of hardness testing equipment uses steel-ball indenters to penetrate metal that is being tested, however, the m
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Answer:

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

Based on the analysis, the 95% confidence interval is specified as (0.2789;3.055)  

The question regarding the 95% confidence interval's ability to ascertain potential differences in measurements between the two indenters is as follows:

Indeed, the confidence interval does not include the value 0, thus indicating that the Diamond values significantly exceed those of the Steel Ball at a 5% significance level.

Step-by-step explanation:

Here is the dataset in consideration:

specimen    1     2    3     4      5     6     7    8     9

Steel Ball   51   57   61   70   68   54   65  51   53

Diamond   53   55  63   74   69   56   68  51   56

By calculating the differences between diamond and steel ball measurements, we create the dataset:

d: 2, -2, 2, 4, 1, 2, 3, 0, 3

In the next step, we compute the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.667

Following that, we determine the standard deviation of the differences, arriving at:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.803

A confidence interval refers to "a range of values that’s likely to encompass a population value with a certain level of confidence. It is typically expressed as a percentage indicating where a population mean falls within an upper and lower limit."  

The margin of error represents the extent to which values diverge above and below the sample statistic in a confidence interval.  

Normal distribution, is described as a "probability distribution that is symmetric about the mean, illustrating that data points close to the mean occur more frequently than those further away."  

The confidence interval for the mean is derived using the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

To calculate the critical value t_{\alpha/2}, we first determine the degrees of freedom using:  

df=n-1=9-1=8  

Given a confidence level of 0.95 or 95%, the appropriate critical value can be found using Excel, a calculator, or a table. The Excel command would be: "=-T.INV(0.025,9)". Therefore, we observe that t_{\alpha/2}=2.31.

Finally, we can substitute all our findings into formula (1):  

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

In this case, the 95% confidence interval is calculated as (0.2789;3.055)  

In determining if the two indenters yield distinct measurements, we find that the confidence interval does not enclose zero, allowing us to conclude that Diamond readings greatly surpass Steel Ball readings at the 5% significance level.

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tester [12383]

Answer:

1. 3.767

2. 0.145

Step-by-step explanation:

Define X as the exam scores and Y as the number of drinks.

X     Y   X-Xbar    Y-Ybar   (X-Xbar)(Y-Ybar)    (X-Xbar)²       (Y-Ybar)²    

75    5    -2.3          2.3          -5.29                      5.29              5.29

92    3     14.7         0.3           4.41                       216.09           0.09

84    2     6.7         -0.7           -4.69                     44.89             0.49

64    4     -13.3        1.3           -17.29                     176.89           1.69

64    2     -13.3       -0.7           9.31                       176.89           0.49

86    7     8.7           4.3           37.41                     75.69            18.49

81     3     3.7           0.3           1.11                         13.69             0.09

61     0    -16.3        -2.7           44.01                     265.69          7.29

73    1      -4.3         -1.7            7.31                        18.49             2.89

93    0    15.7         -2.7           -42.39                    246.49          7.29

sumx=773, sumy=27, sum(x-xbar)(y-ybar)= 33.9, sum(X-Xbar)²= 1240.1,sum(Y-Ybar)²= 44.1

Xbar=sumx/n=773/10=77.3

Ybar=sumy/n=27/10=2.7

1.

Cov(x,y)=sxy=\frac{Sum(X-Xbar)(Y-Ybar)}{n-1}

Cov(x,y)=33.9/9

Cov(x,y)=3.76667

Thus, the sample covariance of exam scores and energy drink consumption is 3.767

2.

Cor(x,y)=r=\frac{Sum(X-Xbar)(Y-Ybar)}{\sqrt{Sum(X-Xbar)^2sum(Y-Ybar)^2} }

Cor(x,y)=r=\frac{33.9}{\sqrt{(1240.1)(44.1)} }

Cor(x,y)=r=33.9/233.85553

Cor(x,y)=r=0.14496

The sample correlation coefficient for the relationship between exam scores and energy drink consumption is 0.145.

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