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Anastasy
1 month ago
5

After a 5% pay raise , Hermione is earning $21,000 per year. What was she earning before the pay raise?

Mathematics
1 answer:
zzz [12.3K]1 month ago
7 0

Answer:

\$20,000

Explanation step-by-step:

Let

x represent Hermione's salary prior to the raise

Given:

100\%+5\%=105\%=105/100=1.05

Therefore, the equation that expresses this relationship is

1.05x=21,000

To find x, divide both sides by 1.05:

x=21,000/1.05

x=\$20,000

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
lawyer [12517]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Details: The cardiac output is assessed using the dye dilution technique with 3 mg of dye.

Goal: To determine the cardiac output value.

Solution:

Cardiac output formula:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Utilize integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Insert the value into 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Consequently, Cardiac output:F=0.055 L\s

4 0
1 month ago
each day last week I sold 32, 45, 47, 63 and 72 product accessories. What was the median number of accessories sold for the week
AnnZ [12381]

Answer:

The median value is 47.

Step-by-step explanation:

First, organize the numbers in ascending order.

The median's position is calculated as ((N+1)÷2)th term, where N is the amount of data.

= 6÷2 th term

= 3 rd term

<ptherefore the="" term="" is="" identified="" as=""> </ptherefore>
4 0
2 months ago
A tooth-whitening gel is to be tested for effectiveness. A group of 85 adults have volunteered to participate in the study. Of t
babunello [11817]

Response:

(a) 3, 5, and 6

Detailed explanation:

In this study, 43 participants will be treated with a gel containing tooth-whitening agents, while the remaining 42 will receive a placebo. Consequently, a placebo is in use.

The selection process for the 43 individuals receiving the gel will be random.

Post-experiment, the whiteness levels of both groups will be compared to analyze the gel's effect.

For true randomness in the experiment, options 3, 5, and 6 are applicable.

(b)

In order for the experiment to be double-blind, the evaluators analyzing the whiteness, as well as the participants, must not know which individuals were given the whitening gel versus the placebo.

5 0
1 month ago
Which statements are true regarding the diagram? Check all that apply.
Zina [12379]

Answer:

2.CE lies on line m.

4.Ray AD is identical to ray AC.

6.Angle ECB is formed by CE and CB.

Step-by-step explanation:

A diagram has been provided.

Our task is to identify the valid statements regarding the diagram.

1.CB is found on line n.

CB does not align with line n since points C and B do not lie on that line.

Thus, this statement is false.

2.CE is situated on line m.

CE is indeed positioned on line m because points C and E are both on this line.

This statement is accurate.

3.Ray BC is equivalent to ray CB.

A ray begins at a single point and continues indefinitely without a terminal point.

Ray CB starts at point C and stretches out from point B.

However, ray BC does not exist.

This statement is therefore false.

4.Ray AD is equivalent to ray AC.

Both AD and AC are rays.

They are equivalent since both originate from point A and extend in the same direction.

5.Angle EAD is formed from AE and DA.

This is false because angle EAD is created by ray AE and ray AD, not by ray DA.

6.Angle ECB is generated by CE and CB.

This is true as angle ECB is made by ray EC and ray BC.

5 0
1 month ago
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If g(x)=4x^2-16 were shifted 5 units to the right and 2 down, what would the new equation be?
lawyer [12517]
Try this method:
When a graph shifts right, replace 'x' with 'x' minus the number.
When it shifts down, subtract the number from 'y'.
So the final equation becomes: y = 4(x - 5)² - 18.
The answer is A.
4 0
1 month ago
Read 2 more answers
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