Vlad spent 20 minutes on his history homework and then completely solved x math problems that each took 2 minutes to complete. W

A) The cost to send a package that weighs 3.2 pounds is $4.13. Since this weight exceeds 3 pounds but remains below 4 pounds, we have to refer to the pricing that applies to 4-pound packages (see the attached document for pricing details).

b) To illustrate the Media Mail shipping costs based on the weight of the books, a line graph is appropriate. In this graph, the weight in pounds is represented on the x-axis and the shipping costs on the y-axis.

c) The graph depicting the Media Mail shipping costs as a function of book weight will be represented by the equation: f(x) = 2.69 + 0.48(x-1)

Answer: 47/59

Step-by-step explanation:

Answer:

  (1/10)∛100 ≈ 0.4642

Step-by-step explanation:

For a cubic shape with volume V, the edge length is defined as...

  s = ∛V

and the surface area is given by...

  A = 6s² = 6V^(2/3)

The area-to-volume ratio is therefore...

  r1 = A/V = 6V^(2/3)/V = 6V^(-1/3)

When the volume V is increased by a factor of 10, the new area-to-volume ratio becomes...

  r2 = 6(10V)^(-1/3)

Consequently, the change factor for the ratio is...

  r2/r1 = (6(10V)^(-1/3))/(6V^(-1/3)) = 10^(-1/3) = (1/10)∛100

The change in surface area per unit volume results in a factor of (∛100)/10.

___

Example

For a cube with side length 2, the corresponding volume equals 2³ = 8, with a surface area of 6·2² = 24. The resulting area-to-volume ratio is 24/8 = 3.

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The area-to-volume ratio changed by a factor of (0.3∛100)/3 = (∛100)/10, as previously noted.

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Let

s--------> denote the cube's side length

We know that

the volume of a cube is calculated as

if the side length s measures

then

and thus, the volume is defined as

This leads us to conclude

the correct option is

D. A cube with side lengths of 2 feet has a volume of 8 cubic feet.

Answer:

Approximately 59 stacked cups.

Step-by-step explanation:

We have the following measurements:

Height of one cup = 12.5 cm,

Height of two cups stacked = 14 cm,

Height of three cups stacked = 15.5 cm,

...and so on.

This situation can be described by an arithmetic sequence,

12.5, 14, 15.5,....

The first term is defined as a = 12.5,

with a common difference of d = 1.5 cm.

Thus, the height of x stacked cups is given by

As per the problem,

h(x) = 200

⇒ 1.5x + 11 = 200

⇒ 1.5x = 189

⇒ x = 59.3333333333 ≈ 59.

Therefore, you will need approximately 59 stacked cups.