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SOVA2
1 day ago
6

True or false: the regression sum of squares (ssr) can never be greater than the total sum of squares (sst).

Mathematics
1 answer:
Svet_ta [9.4K]1 day ago
8 0
............................/............................ 
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Fill in the blanks. a. A​ relative-frequency distribution is to a variable as a​ __________ distribution is to a random variable
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Answer:

a. A relative-frequency distribution relates to a variable just as a _____probability_____ distribution relates to a random variable. b. A relative-frequency histogram pertains to a variable similarly to how a _____probability_____ histogram pertains to a random variable.

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A cosmetic company tested a new lotion. Of the 2,500 people tested 15 had an allergic reaction. What percentage of the people ha
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Sin70cos10-cos70sin10
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Using the identity sin(a-b) = sina.cosb - cosa.sinb

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4 days ago
Find the value of x in the triangle shown below
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The spending limit on John’s credit card is given by the function f(x)=15,000+1.5x , where x is his monthly income. f^-1x . The
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1. "The limit on John's credit card is defined by the function f(x)=15,000+1.5x," indicating that if John's monthly income is $5,000, he can spend a maximum of f(5,000)=15,000+1.5*5,000=15,000+ 7,500=22,500 (dollars). As another example, if John's monthly income is $8,000, then he can spend up to f(8,000)=15,000+1.5*8,000=15,000+ 12,000=27,000 (dollars). 2. If we consider the maximum amount John can spend as y, it can be represented as y=15,000+1.5x. To express x, the monthly income, in terms of y, we rearrange this equation: y=15,000+1.5x results in 1.5x = y-15,000. Therefore, in functional notation, x is a function, referred to as g, based upon y, the maximum sum. Generally, we denote the variable of a function by x, so we redefine g as: This tells us that if the maximum amount that John can spend is $50,000, then his monthly income would be $23,333. 3. If John's limit is $60,000, his monthly income equals $30,000. Note: g is deemed as the inverse function of f because it reverses the actions of f.
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