In the case of an equilateral triangle ABC, each angle measures 60 degrees, as the total angle sum in any triangle is 180 degrees, and dividing that by 3 yields 60. Setting this equal to 3x-12, we have 60 = 3x - 12. After adding 12 to both sides, we get 72 = 3x, and dividing 72 by 3 gives us x = 24.66! I hope this clarifies things for you!
Option B is correct, expressed as 8(25 + x) > 500; solving for x gives x > 37.50
Honestly, I find Mrs. Garcia's method easier to perform mentally. It hinges on how familiar you are with your multiples of 5. (5*15 = 75 is a multiplication I often use)
Melissa's approach involves calculating 5*20 = 100 and 5*9 = 45, then combines the 3-digit result 100 with the 2-digit result 45, yielding 145. Adding 45 to 00 is simple and doesn’t require carrying digits, thus the arithmetic is fairly straightforward.
Mrs. Garcia's technique involves computing 5*14 = 70 and 5*15 = 75, then summing these two-digit results. Many people may not readily recall that 5*15=75, which complicates forming that product. The addition of 70 and 75 requires a carrying operation, making the math somewhat more complex. The resulting total is 145.
(The rationale behind my preference for Mrs. Garcia's method is that I can achieve the final sum by simply doubling 7 tens, followed by adding 5. The only 3-digit number to remember mentally is the ultimate total.)
_____Subtraction introduces a slight complication, yet reshaping it as $5(30 -1) = $150 - 5 = $145 is possible.
Or, you may reframe it as $5(28 +1) = $140 +5 = $145.
Dividing an even number by 2 to find the product of 5 is straightforward when you append a zero.
5*14 = 10*7 = 70
5*28 = 10*14 = 140.
Answer:
At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.
Step-by-step explanation:
A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.
The null and alternative hypotheses are:
The significance level is set at 0.10.
The sample mean recorded is 17, and the sample standard deviation is 5.37.
The degrees of freedom are calculated as df=(20-1)=19.
The t-statistic is:
The two-tailed P-value corresponding to t=1.67 is P=0.11132.
<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.
At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.
Set G consists of: G={4, 8, 12, 16, 20, 24, 28, 32, 36,...} Set F represents the perfect squares: F={1, 4, 9, 16, 25, 36, 49, 64, 81, 100...} Within set F, the numbers 4, 16, 36, 64, and 100 are multiples of 4. The result is: {4, 16, 36, 64, 100}.
