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1 month ago

How many molecules are in 0.25 grams of dinitrogen pentoxide?

Chemistry

2 answers:

alisha [2.9K]1 month ago

7 0

Answer: $0.014\times 10^{23}molecules$

Explanation: Moles are determined using the formula:

$\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}$

$\text{no of moles}=\frac{0.25g}{108g/mol}=0.002moles$

1 mole of $N_2O_5$ contains = $6.023\times 10^{23}molecules$

0.002 mole of $N_2O_5$ contains = $\frac{6.023\times 10^{23}}{1}\times 0.002=0.014\times 10^{23}molecules$

eduard [2.7K]1 month ago

4 0

To determine the answer, you need to understand the formula for converting grams to moles, which will then lead you to the number of molecules.
The result is 2 moles of N2O5. The process is as follows:
(0.25 g N2O5) (1 mol/ 108 g)=2.31 molecules
Thus, the final answer is 2 molecules.

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Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.

Alekssandra [3086]

Response: The moles in 369 grams of calcium hydroxide are 4.98 moles

Reasoning: Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used:

$\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}$

Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.

$\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole$

Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0

1 month ago

Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversi

Tems11 [2777]

Answer:

15.71g

Explanation:

The combustion equation that applies to hydrocarbons is

CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O

In the case of octane, C8H18:

C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O

C8H18 + 50/4 O2 = 8CO2 + 9H2O

C8H18 + 25/2 O2 = 8CO2 + 9H2O

2C8H18 + 25 O2 = 16 CO2 + 18H2O (this is the balanced equation)

From this balanced reaction,

2 x 22.4 L of octane generates 16 [ 12 + (16 x 2)] of carbon dioxide

That means,

44.8 L of octane generates 704g of carbon dioxide

Thus, for 1L of octane, it produces 1 L x 704g/44.8 L = 15.71g of carbon dioxide

Consequently, 15.71g of carbon dioxide is produced from the complete combustion of 1 L of octane.

7 0

2 months ago