Answer:
THE MOLAR MASS OF XCL2 IS 400 g/mol
THE MOLAR MASS OF YCL2 IS 250 g/mol.
Explanation:
We derive the molar mass of XCl2 and YCl2 by recalling the molar mass formula when both mass and the number of moles are known.
Number of moles = mass / molar mass
Molar mass = mass / number of moles.
For XCl2,
mass = 100 g
number of moles = 0.25 mol
Thus, molar mass = mass / number of moles
Molar mass = 100 g / 0.25 mol
Molar mass = 400 g/mol.
For YCl2,
mass = 125 g
number of moles = 0.50 mol
Molar mass = 125 g / 0.50 mol
Molar mass = 250 g/mol.
Accordingly, the molar masses for XCl2 and YCl2 are 400 g/mol and 250 g/mol, respectively.
Answer:
Explanation:
The relationship between the new temperature scale and the absolute temperature scale is defined as follows
Aw = 2 K
for K = 273.15 (the freezing point of water on the absolute scale)
Aw = 2 x 273.15 = 546.3 K
Each division of the new scale is equivalent to half that of each division on the absolute scale
each division of the new scale is minimal.
The value of R = 8.314 J per mole per K
Here, per K corresponds to 2Aw
Hence, the value of R in the new scale = 8.314/2 J per mole per Aw
= 4.157 J per mole per Aw
k = R / N
= 4.157 / 6.02 x 10²³
= .69 x 10⁻²³
= 6.9 x 10⁻²⁴ J per molecule per Aw .
Respuesta:
El oxígeno en H2O2 es la especie que se reduce a H2O y se oxida a O2.
Explicación:
5 H2O2(aq) + 2 MnO4-(aq) + 6 H+(aq) → 2 Mn2+(aq) + 8 H2O(l) + 5 O2(g)
La oxidación se define como la pérdida de electrones. La oxidación provoca un aumento en el número de oxidación de un elemento.
Si se descompone esta reacción en sus mitades de reducción y oxidación
Se observa que, de los reactivos mencionados anteriormente,
H202 se convierte en H2O y O2
MnO4- + H+ se convierte en Mn2+ y H2O
El número de oxidación de Mn cambia de +7 en MnO4- a +2 en Mn2+ (lo que indica evidentemente una reducción)
El oxígeno en MnO4- no cambia su número de oxidación, ya que se mantiene en -2
El número de oxidación del oxígeno cambia de -1 en H2O2 a -2 en H2O y 0 en O2
El hidrógeno en H2O2 no cambia su número de oxidación, y su número de oxidación se mantiene en +1 tanto en H2O2 como en H2O.
Esto indica que H2O2 sufre tanto oxidación como reducción; más específicamente, el oxígeno en H2O2 es la especie que se reduce a H2O y se oxida a O2.
Espero que esto ayude
Answer:
(C) The average speed of molecules in ethane is the same as that of propanol.
Explanation:
In gas behavior, temperature is directly linked with speed. At a constant temperature, speed remains consistent. Also, we understand that ideal gases exhibit uniform behavior, irrespective of their type.
Answer:
The adjustable legs along with the sand table.
Note: The question is incomplete. The full question is presented below.
Using Models to Address Questions Regarding Systems
Armando’s class was examining images of rivers shaped by flowing water. Most rivers appeared wide and shallow, except for one, which was narrow and deep. The students theorized that this river's narrowness and depth are due to:
- the steepness of the hill from which the water descends, or
- the diminutive size of the sand grains the water flows through.
To explore the answer to the question of why this river is so narrow and deep, Armando created the model outlined below.
Explanation:
The model constructed by Armando will facilitate addressing the question due to specific features:
1. Adjustable leg - as one theory proposed by the class suggests that the steep hill affecting the water's path could be the reason for the river's dimensions, the adjustable legs are designed to be raised or lowered to alter the slope, allowing testing of this theory.
2. Sand table - this acts as the streambed. By modifying the size of the sand grains, students can examine the second hypothesis that smaller sand grains contribute to the river's narrowness and depth.
The outcomes of their experimentation will lead them to a conclusion.
