Answer:
There is ample evidence to substantiate the assertion that the standard deviation of the duration all women take to wash their hair in the morning is 15 seconds
Step-by-step explanation:
We must first articulate the hypotheses while comprehending the statement’s context. The assertion claims that the standard deviation of time spent washing hair in the morning by all women is 15 seconds. In mathematical symbols, we express this as follows:
σ = 15
The presence of an equality sign qualifies this assertion as our null hypothesis;
H0: σ = 15
Our alternative hypothesis is the negation of the prior hypothesis;
Ha: σ ≠ 15
We learn that the preliminary outcome of the test does not reject the null hypothesis. In simple terms, this indicates that we do not reject the assertion that the standard deviation of time all women spend washing their hair in the morning is, in fact, 15 seconds, as this assertion represents our null hypothesis. A failure to reject a hypothesis during testing signifies that there is enough evidence to support it. Hence, there is enough evidence to affirm that the standard deviation of time all women spend washing their hair in the morning is 15 seconds
Y - 52 = (580 - 52)/(8 - 2) (x - 2)
y - 52 = 528/6 (x - 2) = 88(x - 2)
y = 88x - 176 + 52
y = 88x - 124
Possible outcomes:
Heads Heads
Heads Tails
Tails Tails
Tails Heads
Probability of matching: 2/4 = 0.5
Torin should consent since the suggestion is equitable
Response:
Alan's survey aims to determine the art preferences among students at the local high school.
To conduct a thorough investigation, he needs to consider all students in the school as the target population since that is his goal.
Nevertheless, in many cases involving statistical studies, it's impractical to include the entire population. In such instances, a sample that accurately reflects the overall student body is employed.
This sample is a subset of the population and must share the same characteristics and attributes; otherwise, the findings may be skewed.
Thus, a feasible sample would consist of a specific number of students from each grade level, including freshmen, sophomores, juniors, and seniors. This approach ensures the sample accurately represents the larger population.
1 cg equals 10^-5 kg
Thus, 8.25 * 10^2 cg converts to 8.25 * 10^-3 kg
1 nanogram is represented as 10^-12 kg
Consequently, 8.25 * 10^-3 kg is equivalent to 8.25 * 10^9 nanograms
As a result, 8.25 * 10^2 cg is equal to 8.25 * 10^9 nanograms.
