GRAHAM CORPORATION

Answer:

Attached is the question in consideration.

forms a straight line.

depicts a right triangle.

The options represent the correct answers.

Step-by-step explanation:

⇒ Given that  is ⊥ it constitutes a right triangle, leading to .

⇒ The measure for equals as bisects , implying that is half of , thus  .

⇒ represents a straight line, as the angle measures across it yield .

⇒ The angle measure for is derived from the linear pair concept.

Since , inserting the values of   leads to .

The other two options are incorrect as:

• 

       it surpasses while is a               

      straight line.

• Also, is inaccurate.

     As and

Thus, we have a total valid answers.

The confirmed options are .

The equation that demonstrates a proportional relationship, maintaining a constant of proportionality equal to 14, is: Here,  and are proportional with a constant of proportionality of 14.

B. f(x)=-1/3x^4+7x^2+15. You can visualize the function using a graphing tool for better understanding.

Answer:

A) Maia had 1920 beads more.

B) Maia had 2544 beads at first.

Step-by-step analysis:

Let x denote the beads with Jenny and y for Maia.

The information provided states that Maia possesses 2064 beads more than Jenny, which can be represented mathematically as:

Additionally, after Maia made a necklace with 144 beads, she had five times more beads than Jenny.

This can also be formulated as an equation:

A) Since Maia had 2064 beads more than Jenny before using 144 beads, we calculate her final bead count by subtracting 144 from 2064.

Thus, Maia is left with 1920 beads more than Jenny.

B) To solve this system of linear equations, we will utilize the substitution method.

By inserting equation (1) into equation (2), we arrive at:

Now, let's divide our equation by 4.

Now, we'll substitute x=480 into equation (1) to isolate y.

Conclusively, Maia initially had 2544 beads.

Answer:

Step-by-step explanation:

The total count of laptops, N = 20

Defective laptops, n = 3

The school is purchasing 2 laptops

Case 1:

Both purchased laptops are non-defective

Probability of selecting 2 non-defective laptops

The count of non-defective laptops equals 20 - 3 = 17

Overall laptop count = 20

Probability, P = 17/20 = 0.85

Case 2:

One laptop is found defective

The probability of choosing 1 defective and 1 non-defective laptop

P' = 3/20 x 17/19 = 0.134

Case 3:

Both laptops are defective

Choosing 2 laptops from 3 = 3 C 2 = 3

Selecting 2 from 20 = 20 C 2 = 190

The probability of selecting two defective laptops equals 3 / 190 = 0.0158

P'' =