Answer:
(A) 0.15625
(B) 0.1875
(C) Cannot be determined
Step-by-step explanation:
The time it takes for a student to finish a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let's denote X as the duration needed for the student to complete the statistics quiz
Thus, X ~ U(32, 64)
The probability density function (PDF) for a uniform distribution is expressed as;
f(X) = 
, a < X < b where a = 32 and b = 64
The cumulative distribution function (CDF) is given by P(X <= x) = 
(A) The probability of a student taking longer than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 - = 1 - 
= 
= 0.15625
(B) The probability that a student completes the quiz between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) = 
= 
= 0.34375
P(X < 37) = 
= 
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) The probability that a student takes exactly 44.74 minutes to complete the quiz
= P(X = 44.74)
This probability cannot be calculated as it is a continuous distribution, which doesn't provide probabilities for specific points.
Step-by-step explanation:
When a negative number is placed within a modulus function, the result will be positive. For instance, |-3| equals 3, |-6| equals 6, and |5| equals 5, etc.
A modulus function, expressed as |x|, is always positive unless x is zero, in which case it equals zero.
Consequently, |x| cannot be less than -4 because |x| is always non-negative. Thus, the statement is inaccurate.
Answer:
When you divide 360 by 5, you get 72; a full circle measures 360 degrees
The range consists of all the valid y values, starting from 5.
Response:
e. 545
Detailed explanation:
In a survey sample containing n individuals, with a success probability of 
, and a confidence level of 
, the ensuing confidence interval for proportions is established.
Wherein
z denotes the z-score corresponding to a probability value of 
.
For this scenario, we find:
The estimate averages the two bounds. Thus 
95% confidence level
Consequently, z represents the z value corresponding to the p-value of 
, hence 
.
The lower boundary of this interval is:
In this query, L = 0.82. Therefore
Thus, the accurate response is:
e. 545
