(5r - 4)(r² - 6r + 4)
uses the distributive property for multiplication.
This expands to 5r(r² - 6r + 4) - 4(r² - 6r + 4)
which results in 5r³ - 30r² + 20r - 4r² + 24r - 16
as you combine like terms and simplify.
The outcome is 5r³ - 30r² - 4r² + 20r + 24r - 16
leading to a final expression of 5r³ - 34r² + 44r - 16. Choice A.
1.) <span>The ratio of note A compared to middle C is 440.0 / 261.6 = 1.6820 ≈ 1.6818
2.) </span><span>The D note's ratio against middle C is 293.7 / 261.6 = 1.1227
3.) </span><span>D# = 293.6 multiplied by 1.0595 equals 311.1
4.) </span><span>The frequency ratio of G compared to C is 1: 262/392 = 1: 0.6683 ≈ 3: 2
5.) </span><span>The frequency ratio of E to C is 1: 262/330 = 1: 0.7939 ≈ 5: 4
6.) The </span><span>element in a musical note referred to as pitch is the frequency.</span>
Answer: 11, 13
Explanation:
We need to identify two consecutive integers whose product is 143. If we let x represent the larger of the two integers, the smaller integer can be expressed as (x-2). Their product equals 143, which gives us

By solving the equation:

this results in a second-order equation with two real roots: x=13 and x=-11. We disregard the negative outcome, leaving us with x=13. Hence, the two numbers are
x=13
x=13-2=11
Answer:
3x = 12
x = 4
Step-by-step explanation:
The equation indicates that the distance to the dance class is three times that to her home, and when multiplied by "x", it reveals how much farther 3 is from 12. Consequently, if you evaluate the expression, the distance to the dance class is four times greater than that to her music class.