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quester
6 days ago
12

Mark noticed that his bus is late to school 5% of the time. He wants to design a spinner he can use to simulate the situation an

d determine the probability that the bus will be late three times next week. How should Mark divide his spinner to best simulate the situation?
Mathematics
2 answers:
PIT_PIT [3.9K]6 days ago
5 0

A meticulous method to create this would involve partitioning the spinner into 100 segments and coloring 5 of those. This results in a probability of 5/100 = 0.05 = 5%, indicating that each of the 5 segments has a 5% likelihood of being landed upon.

A more efficient approach is to split it into 20 segments instead. This works because simplifying 5/100 yields 1/20 (by dividing both the numerator and denominator by 5). Thus, instead of coloring in 5 segments, Mark should just color 1. If you check this with a calculator, you’ll see that 1/20 = 0.05 = 5% too.

The second choice is more efficient, but a spinner with 20 pieces is still somewhat cumbersome. It may be more practical for Mark to draw random numbers from a hat or use a computer to generate random numbers.

Zina [3.9K]6 days ago
4 0

Answer:

The solution is to divide it into 20 equally-sized sections.

Step-by-step explanation:

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2 days ago
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a resorvoir can be filled by an inlet pipe in 24 hours and emptied by an outlet pipe 28 hours. the foreman starts to fill the re
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To determine the rates at which the inlet and outlet pipes fill and empty the reservoir, we remember that work done equals rate multiplied by time. Let’s denote the inlet rate as i and for the outlet pipe as 0. Therefore,
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In this context, the '1' represents the total number of reservoirs, since the problem states the time needed for each pipe to either fill or empty a singular reservoir. Solving for rates yields:
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Over the first six hours, the inlet pipe fills (1/24)(6) = 1/4 reservoirs and during the same period, the outlet pipe empties (1/28)(6) = 3/14 reservoirs. To calculate the net volume of the reservoir filled, we subtract the emptying total from the filling total:
1/4 - 3/14 = 1/28 reservoirs (note that if emptying exceeds filling, a negative value results. In such cases, treat that negative value as zero, indicating that the outlet rate surpasses the inlet rate, leading to an empty reservoir).
Now we need to find out how long it will take to fill up one reservoir since we’ve already partially filled 1/28 of it, after closing the outlet pipe. In simpler terms, we need to determine the time required for the inlet pipe to finish filling the remaining 27/28 of the reservoir. Fortunately, we have already established the filling rate for the inlet pipe, leading to the equation:
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7 days ago
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. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i
PIT_PIT [3919]

Answer:

Error made by Andrew: He identified incorrect factors based on the roots.

Step-by-step explanation:

The roots of the polynomial consist of: 3, 2 + 2i, 2 - 2i. By the factor theorem, if a is a root of the polynomial P(x), then (x - a) must be a factor of P(x). According to this premise:

(x - 3), (x - (2 + 2i)), (x - (2 - 2i)) represent the factors of the polynomial.

<pBy simplification, we obtain:

(x - 3), (x - 2 - 2i), (x - 2 + 2i) as the respective factors.

This is where Andrew's mistake occurred. Factors should always be in the form (x - a), not (x + a). Andrew expressed the complex factors incorrectly, resulting in an erroneous conclusion.

Thus, the polynomial can be expressed as:

(x - 3)(x - 2 - 2i)(x - 2+2i)=0\\\\ (x-3)(x^{2}-2x+2xi-2x+4-4i-2xi+4i-4i^{2})=0\\\\ (x-3)(x^{2}-4x+4+4)=0\\\\ (x-3)(x^{2}-4x+8)=0\\\\ x^{3}-4x^{2}+8x-3x^{2}+12x-24=0\\\\ x^{3}-7x^{2}+20x-24=0

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