Mark noticed that his bus is late to school 5% of the time. He wants to design a spinner he can use to simulate the situation an

Response:    ∠B = 42°   ∠A = 23°  ∠F = 115°

Detailed explanation:

∠B is congruent to ∠C  alternate interior angles  42°

  ∠CDF is supplementary to ∠CDE,

thus m∠CDF = 23°  and ∠FAB is congruent to ∠CDF therefore m∠FAB= 23°

also ∠A is congruent to ∠CDE  corresponding angles  157° ∠FAB is supplementary to ∠A

which leads to 180 - 157 = 23 giving m∠FAB

The sum of angles in a triangle amounts to 180°, so m∠AFB = 180 -(23 +42)

This results in 180- 65 = 115 = m∠F

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) To find P(X=2), we calculate: P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4) which equals 1 - 0.41 - 0.18 - 0.06 - 0.06, resulting in 0.29

b) For P(X<2), we sum P(X=0) and P(X=1): 0.41 + 0.18 yields 0.59

c) To obtain P(X≤2), we add P(X=0), P(X=1), and P(X=2): 0.41 + 0.18 + 0.29 equals 0.88

d) To calculate P(X>2), we find P(X=3) + P(X=4): 0.06 + 0.06 gives us 0.12

e) For P(X=1 or X=4), we use the union of probabilities: P(X=1) + P(X=4) which is 0.18 + 0.06, resulting in 0.24

f) P(1≤X≤4) is found by adding P(X=1), P(X=2), P(X=3), and P(X=4): 0.18 + 0.29 + 0.06 + 0.06 results in 0.59

Response:

404 instances

Detailed breakdown:

Bart needs to;

Calculate 6(400), 6(10), and 6(2) ⇒ 2nd

Calculate each addend multiplied by 6 ⇒ 4th

Determine the total of (2400 + 60 + 12) ⇒ 5th

Step-by-step breakdown:

We'll review the distributive property

• a(b + c) = ab + ac
• a(b + c + d) = ab + ac + ad

Bart applied place value along with the distributive property to express the

calculation 6(412)

His calculation can be represented as 6(412) = 6(400 + 10 + 2)

We must find out what Bart needs to do to compute the product

∵ 6(412) = 6(400 + 10 + 2)

- Multiply every component inside the brackets by 6 on the right side

∴ 6(400 + 10 + 2) = (6)(400) + (6)(10) + 6(2)

∴ 6(400 + 10 + 2) = 2400 + 60 + 12

∴ He should multiply each addend by 6, then calculate the total of

  (2400 + 60 + 12)

Bart needs to;

Calculate 6(400), 6(10), and 6(2)

Multiply each addend by 6

Compute the total of (2400 + 60 + 12)

Learn more:

You can find additional information regarding place value at