Objects in vertical motion are an illustration of non-uniform motion. At the peak of the circle, centripetal force is balanced by the object's weight. Therefore, the minimum speed required at this top point is given by v =

=

= 5.23 m/s. As the sphere descends from the top to the bottom of the circle, according to the law of conservation of energy, potential energy can be expressed as

, where h signifies the diameter of the circle (2r). Hence, the expression will be written as

where u is the velocity at the lowest point. Consequently, the modified equation is
= 
= 
= 11.71 m/s. The collision of the dart with the bullet is an inelastic one. According to the conservation of momentum: v = 
= 
= 
= 58.55 m/s. Thus, the dart's minimum initial speed for the combined system to complete a circular loop post-collision is 58.55 m/s.
Answer:
H = 109.14 cm
Explanation:
Given,
Assume that the total energy equals 1 unit.
Energy remaining after the first collision = 0.78 x 1 unit
Balance after the first impact = 0.78 units
Remaining energy after the second impact = 0.78 ^2 units
Balance after the second impact = 0.6084 units
Remaining energy after the third impact = 0.78 ^3 units
Balance after the third impact = 0.475 units
The height reached after the third collision is equivalent to the remaining energy.
Let H denote the height achieved after three bounces.
0.475 (m g h) = m g H
H = 0.475 x h
H = 0.475 x 2.3 m
H = 1.0914 m
H = 109.14 cm
Answer:
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Explanation: